The kinetic energy of 6250 J equals 6250 J work-done in stopping the object in motion.
The given parameters;
- <em>Kinetic energy, K.E = 6250 J</em>
According to work-energy theorem, the work done in stopping a moving object is equal to the kinetic energy of the moving object.
Kinetic energy is the energy possessed by an object by virtue of its state of motion.
Work-done in stopping the object in motion = K.E = 6250 J.
Thus, we can conclude that the kinetic energy of 6250 J equals 6250 work-done in stopping the object in motion.
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Answer:
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</u><u>2 2 pyruvic acid
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