Please help ! thank you

Mathematics

1 answer:

tankabanditka [31]2 years ago

6 0

That would be

$\dfrac{.24}{.54} = .444...$

Answer: B

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Sophie [7]

C
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c:

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2 years ago

A certain genetic condition affects 8% of the population in a city of 10,000. Suppose there is a test for the condition that has

enot [183]

Solution:

Population in the city= 10,000

As genetic condition affects 8% of the population.

8 % of 10,000

$=\frac{8}{100}\times 10,000=800$

As, it is also given that, there is an error rate of 1% for condition (i.e., 1% false negatives and 1% false positives).

So, 1% false negatives means out of 800 tested who are found affected , means there are chances that 1% who was found affected are not affected at all.

So, 1% of 800 $=\frac{1}{100}\times 800=8$

Also, 1% false positives means out of 10,000 tested,[10,000-800= 9200] who are found not affected , means there are chances that 1% who was found not affected can be affected also.

So, 1% of 9200 $=\frac{1}{100}\times 9200=92$

1. Has condition Does not have condition totals = 800

2. Test positive =92

3. Test negative =8

4. Total =800 +92 +8=900

5. Probability (as a percentage) that a person has the condition if he or she tests positive= As 8% are found positive among 10,000 means 9200 are not found affected.But there are chances that out of 9200 , 1% may be affected

$=\frac{\text{1 percent of 9200}}{9200}\\\\ \frac{\frac{1}{100}\times 9200}{9200}=\frac{92}{9200}\\\\ =0.01$