Answer
Pressure, P = 1 atm
air density, ρ = 1.3 kg/m³
a) height of the atmosphere when the density is constant
Pressure at sea level = 1 atm = 101300 Pa
we know
P = ρ g h
h = 7951.33 m
height of the atmosphere will be equal to 7951.33 m
b) when air density decreased linearly to zero.
at x = 0 air density = 0
at x= h ρ_l = ρ_sl
assuming density is zero at x - distance
now, Pressure at depth x
integrating both side
now,
h = 15902.67 m
height of the atmosphere is equal to 15902.67 m.
To solve this problem we will apply the concepts related to power as a function of the change of energy with respect to time. But we will consider the energy in the body equivalent to kinetic energy. The change in said energy will be the difference between the two velocity data given by half of the mass. We will first convert the given units into an international system like this
Initial Velocity,
Final Velocity,
Now Power is defined as the change of Energy over the time,
But Energy is equal to Kinetic Energy,
Replacing,
Therefore the correct answer is A.
Answer: 3.3 x 10^-28 J
Explanation: just answered on a quiz!! :)
Answer:
0.912
Explanation:
Given that
Height of bouncing of the ball, h = 1.71 m
Number of times the ball bounced, n = 4 times
Height from which the ball was dropped, H = 2.47
First, let's start by defining what coefficient of restitution means
Coefficient of Restitution, CoR is the "ratio of the final to initial relative velocity between two objects after they collide. It normally ranges from 0 to 1 where 1 would be a perfectly elastic collision."
It is mathematically represented as
CoR = (velocity after collision) / (velocity before collision)
1.71 = 2.47 * c^4, where c = CoR
1.71/2.47 = c^4
c^4 = 0.6923
c = 4th root of 0.6923
c = 0.912
