Answer:
The total surface area of this square pyramid is 
Step-by-step explanation:
we know that
The surface area of a square pyramid is equal to
![SA=b^{2} +4[\frac{1}{2}(b)(h)]](https://tex.z-dn.net/?f=SA%3Db%5E%7B2%7D%20%2B4%5B%5Cfrac%7B1%7D%7B2%7D%28b%29%28h%29%5D)
we have
----> the length side of the square base
----> the height of the triangular faces
substitute the values
![SA=9^{2} +4[\frac{1}{2}(9)(12)]=297\ mm^{2}](https://tex.z-dn.net/?f=SA%3D9%5E%7B2%7D%20%2B4%5B%5Cfrac%7B1%7D%7B2%7D%289%29%2812%29%5D%3D297%5C%20mm%5E%7B2%7D)
Answer: 7(sin 50 degrees)
Step-by-step explanation:
4(x + 7) = 38
Since there is no operation sign between the 4 and parenthesis, it makes it an automatic multiplication problem.
You would use distributive property to multiply each which should leave your equation looking like this afterwards:
4x + 28 = 38
(4 times x and 4 times 7)
You would then solve it like a two step equation,
1. +28 - 28 = 0
2. 38 - 28 = 10
4x = 10
10 divided by 4 = 2.5
x = 2.5
We can recheck our work by substituting in the value of x.
4(2.5 + 7) = 38
10 + 28 = 38
When we substituted in the value, it gave us the correct inequality.
Therefore,
x = 2.5
Answer: C) exactly one triangle
<u>Step-by-step explanation:</u>
Given: ∠A = 45°, ∠B = 65°, side c = 4 cm
By the Triangle Sum Theorem, ∠C = 70°
Now you have a proportion so you can use the Law of Sines to find the exact length of side a and of side b.
Thus, there is exactly one triangle.
(t^2+1)^100
USE CHAIN RULE
Outside first (using power rule)
100*(t^2+1)^99 * derivative of the inside
100(t^2+1)^99 * d(t^2+1)
100(t^2+1)^99 * 2t
200t(t^2+1)^99
