What does change and what does NOT change during a translation? *

Mathematics

2 answers:

Basile [38]3 years ago

7 0

Answer:

the size and the shape

Step-by-step explanation:

nalin [4]3 years ago

6 0

Answer:

During a translation the location of a figure changes, but the orientation, area, and lengths between it's points do not.

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Find all real numbers s such that -2(s - 7) > 4s + 8. Give your answer as an interval.

aev [14]

If -2 (s - 7) > 4s + 8
then -2s + 14 > 4s + 8
14 - 8 > 4s + 2s
6 > 6s

∴ <span>all real numbers s such that -2(s - 7) > 4s + 8 are s < 1</span>

7 0

4 years ago

How do you do this problem? I need to know how you found the answer.

Alexxandr [17]

to get the equation of a line, we simply need two points, say for the Red one ... notice in the graph the lines passes through (0,2) and (-1,6), so let's use those

$\bf (\stackrel{x_1}{0}~,~\stackrel{y_1}{2})\qquad (\stackrel{x_2}{-1}~,~\stackrel{y_2}{6}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{6-2}{-1-0}\implies \cfrac{4}{-1}\implies -4 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-2=-4(x-0) \\\\\\ y-2=-4x\implies \blacktriangleright y=-4x+2 \blacktriangleleft$

now, for the Blue one, say let's use hmmm it passes through (0,2) and (1.6)

$\bf (\stackrel{x_1}{0}~,~\stackrel{y_1}{2})\qquad (\stackrel{x_2}{1}~,~\stackrel{y_2}{6}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{6-2}{1-0}\implies \cfrac{4}{1}\implies 4 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-2=4(x-0) \\\\\\ y-2=4x\implies \blacktriangleright y=4x+2 \blacktriangleleft$