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choli [55]
3 years ago
5

Given the trinomial 3x^2 − 6x 5, what is the value of the discriminant? -66 -24 8 96

Mathematics
1 answer:
lbvjy [14]3 years ago
8 0
3x^2-6x+5

for ax^2+bx+c=0
discriminant is b^2-4ac
when
1. b^2-4ac>0, there are 2 real roots
2. b^2-4ac=0, there is 1 real root
3. b^2-4ac<0, there are  2 complex roots


3x^2-6x+5
a=3
b=-6
c=5
(-6)^2-4(3)(5)
36-60
-24

answer is -24 is the discriminant
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Use the given angle measures to find the indicated
mina [271]

Answer:

x = -9°

m∠A = 37°

Step-by-step explanation:

(8-5x) + (10-3x) = 90

8-5x + 10-3x = 90

18-8x = 90

-8x = 72

x = -9°

m∠A = 10- (-9*3) =

10-(-27) = 37°

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Solve. Use the basic percent equation. 212.5 is 85% of what?
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Answer:

250

Step-by-step explanation:

85% · n = 212.5

[convert 85% to .85]

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Domain and Range for the function f(x)=5IXI is
shutvik [7]

Answer:

The domain of the function f(x) is:

\mathrm{Domain\:of\:}\:5\left|x\right|\::\quad \begin{bmatrix}\mathrm{Solution:}\:&\:-\infty \:

The range of the function f(x) is:

\mathrm{Range\:of\:}5\left|x\right|:\quad \begin{bmatrix}\mathrm{Solution:}\:&\:f\left(x\right)\ge \:0\:\\ \:\mathrm{Interval\:Notation:}&\:[0,\:\infty \:)\end{bmatrix}

Step-by-step explanation:

Given the function

f\left(x\right)=5\left|x\right|

Determining the domain:

We know that the domain of the function is the set of input or arguments for which the function is real and defined.  

In other words,  

  • Domain refers to all the possible sets of input values on the x-axis.

It is clear that the function has undefined points nor domain constraints.

Thus, the domain of the function f(x) is:

\mathrm{Domain\:of\:}\:5\left|x\right|\::\quad \begin{bmatrix}\mathrm{Solution:}\:&\:-\infty \:

Determining the range:

We also know that range is the set of values of the dependent variable for which a function is defined.  

In other words,  

  • Range refers to all the possible sets of output values on the y-axis.

We know that the range of an Absolute function is of the form

c|ax+b|+k\:\mathrm{is}\:\:f\left(x\right)\ge \:k

k=0

so

Thus, the range of the function f(x) is:

\mathrm{Range\:of\:}5\left|x\right|:\quad \begin{bmatrix}\mathrm{Solution:}\:&\:f\left(x\right)\ge \:0\:\\ \:\mathrm{Interval\:Notation:}&\:[0,\:\infty \:)\end{bmatrix}

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