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matrenka [14]
3 years ago
8

When Arjun makes hot cocoa, he adds 20\text{ mL}20 mL20, start text, space, m, L, end text of chocolate syrup for every 333 ounc

es of hot water. Arjun's brother, Eli, adds 45\text{ mL}45 mL45, start text, space, m, L, end text of chocolate syrup for every 666 ounces of hot water. Which hot cocoa is more chocolatey? Choose 1 answer: Choose 1 answer:
Mathematics
1 answer:
loris [4]3 years ago
7 0

Answer:

<h3>45mL hot cocoa is more chocolatey</h3>

Step-by-step explanation:

When Arjun makes hot cocoa, if he add 20mL of chocolate syrup to 3ounces of water, let us know the equivalent chocolate in one ounces of water.

20mL = 3 ounces

x = 1 ounce

cross multiply

3x = 20

x = 20/3

x = 6.67 mL

This means he must have add 6.67mL of chocolate to 1 ounce of water.

Similarly, if 45mL is added to every 6 ounces

45mL = 6ounces

x = 1 ounce

cross multiply

6x = 45

x = 45/6

x =  7.5mL

This means he must have add 7.5mL of chocolate to 1 ounce of water.

The hot cocoa that is more chocolatey is the one with the highest amount of chocolate in 1 ounce. That is 45mL hot cocoa

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The snack shop makes 3 mixes of nuts in the following proportions.
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Answer:

A=\begin{bmatrix}6 & 5 & 3\\ 2 & 3 & 4\\ 2 & 2 & 3\end{bmatrix}

B=\begin{bmatrix}25\\ 18\\ 35\end{bmatrix}

Step-by-step explanation:

It is given that the snack shop makes 3 mixes of nuts in the following proportions.

Mix I: 6 lbs peanuts, 2 lbs cashews, 2 lbs pecans.

Mix II: 5 lbs peanuts, 3 lbs cashews, 2 lbs pecans.

Mix III: 3 lbs peanuts, 4 lbs cashews, 3 lbs pecans.

they received an order for 25 of mix I, 18 of mix II, and 35 of mix III.

We need to find the matrices A & B for which AB gives the total number of lbs of each nut required to fill the order.

                      Mix I             Mix II              Mix III

peanuts             6                  5                    3

cashews            2                  3                    4

pecans              2                   2                    2

A=\begin{bmatrix}6 & 5 & 3\\ 2 & 3 & 4\\ 2 & 2 & 3\end{bmatrix}

B=\begin{bmatrix}25\\ 18\\ 35\end{bmatrix}

The product of both matrices is

AB=\begin{bmatrix}6 & 5 & 3\\ 2 & 3 & 4\\ 2 & 2 & 3\end{bmatrix}\begin{bmatrix}25\\ 18\\ 35\end{bmatrix}

AB=\begin{bmatrix}6\cdot \:25+5\cdot \:18+3\cdot \:35\\ 2\cdot \:25+3\cdot \:18+4\cdot \:35\\ 2\cdot \:25+2\cdot \:18+3\cdot \:35\end{bmatrix}

AB=\begin{bmatrix}345\\ 244\\ 191\end{bmatrix}

Therefore matrix AB gives the total number of lbs of each nut required to fill the order.

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4 years ago
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