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Semmy [17]
3 years ago
5

Gianna is going to throw a ball from the top floor of her middle school. When she throws the hall from 48 feet above the ground,

the function h(t)=-16t^2+32t+48 models the height,h, of the ball above the ground as a function of time,t. Find the times the ball will be 48 feet above the ground.
Mathematics
1 answer:
vazorg [7]3 years ago
6 0

Answer:

So, the times the ball will be 48 feet above the ground are t = 0 and t = 2.

Step-by-step explanation:

The height h of the ball is modeled by the following equation

h(t)=-16t^2+32t+48

The problem want you to find the times the ball will be 48 feet above the ground.

It is going to be when:

h(t) = 48

h(t)=-16t^{2}+32t+48

48=-16t^{2}+32t+48

0=-16t^{2}+32t+48 - 48

16t^{2} - 32t = 0

We can simplify by 16t. So

16t(t-2)= 0

It means that

16t = 0

t = 0

or

t - 2 = 0

t = 2

So, the times the ball will be 48 feet above the ground are t = 0 and t = 2.

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