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2 years ago

Select the expression that is equivalent to 40.

Mathematics

1 answer:

Korolek [52]2 years ago

6 0

5x(6+2) because 6+2=8 ans 5x8=40

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Select the correct answer from each drop-down menu. Which system of equations is represented by this graph? Graph shows system o

AleksandrR [38]

The equation of the line going through (-6, 0) and (0, -3) is y = -(1/2)x - 3

The equation of the line going through (0, 3) and (-4, -5) is y = 2x + 3

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more variables and numbers.

The equation of the line going through (-6, 0) and (0, -3) is:

y - 0 = [(-3 - 0) / (0- (-6)](x - (-6))

y = -(1/2)x - 3

The equation of the line going through (0, 3) and (-4, -5) is:

y - 3 = [(-5 - 3) / (-4 - 0)](x - 0)

y = 2x + 3

Find out more on equation at: brainly.com/question/2972832

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7 0

1 year ago

...... ..... .... ....

OleMash [197]

14×2×2×2×2= 224
Chase scored 224 points on thursday

5 0

2 years ago

A 6000-seat theater has tickets for sale at $28 and $40. How many tickets should be sold at each price for a sellout performa

solniwko [45]

Answer:

Manu tickets should $68 for 12

6 0

2 years ago

What the area of this shape is. Please help need to be down by tomorrow!!

puteri [66]

The area of this shape is 12.

Area of a triangle = 1/2 x bh

b= base

h = height

So,

1/2 (6)(4)=12

Hope this helps!

7 0

2 years ago

Read 2 more answers

Which expression is equivalent to (x^4/3 x^2/3)^1/3?

KATRIN_1 [288]

Answer: $x^{\frac{2}{3} }$

Step-by-step explanation:

We have several properties of exponents in use here. The two that are used are:

$(x^{a})(x^{b}) = x^{a + b}$ <em>(Exponents with the same base that are being multiplied together can have the exponents added)</em>

$(x^{a})^{b} = x^{(a)(b)}$ <em>(A base raised to a power, and then raised to another power means that you can multiply the exponents to get the same result as doing inside operations and then outside operations)</em>

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Let's apply it!

First, let's simplify what's inside the parenthesis.

$x^{\frac{4}{3} } x^{\frac{2}{3} }$ <em>(Remember, they have the same base of "x", so we can add the exponents)</em>

$x^{\frac{4}{3} + \frac{2}{3} }$ = $x^{\frac{6}{3} }$ = $x^{2}$

Now we have $(x^{2})^{\frac{1}{3} }$ . Let's use the second rule.

$(x^{2})^{\frac{1}{3} }$ = $x^{\frac{2}{3} }$

Hope this helps! :^)

7 0

3 years ago