X=1/2
Could be your answer
Using multiplication signal rules, it is found that:
A: Emma's statement is always false.
B: The result is always negative.
C: Emma's statement is always true.
The rule used for this exercise is as follows:
- When two numbers of different signals are multiplied, the result is negative.
- When two numbers have the same signal, the result is positive.
Part A:
- Three numbers are multiplied, all negative.
- The multiplication of the first two result in a positive number.
- Then, this positive number is multiplied by a negative number, and the result will be negative, which mean that Emma's statement is always false.
Two examples are:


Part B:
The rule is that the result is always negative.
Part C:
- The multiplication of the first two negative numbers result in a positive number.
- Then, this positive number is multiplied by another positive number, and the result will be positive, which mean that Emma's statement is always true.
Two examples are:


A similar problem is given at brainly.com/question/24764960
Answer:
it is 1/8- 5/8 smallest to biggesst
Here is the answer if you can't read my writing than just ask. also if you have any questions about how I got something feel free to ask
First one:
you can add -10m and -13m but you can't add -10m and 2m^4 becuase the powers aren't the same so
when adding the like terms
look at the:
powers, (x^3 adds with x^3)
placehloder letter (x adds with x and y adds with y and so on)
-10m+2m^4-13m-20m^4
powers: m^1 and M^4
placeholders: all m
add
-10m-13m+2m^4-20m^4
-23m-18m^4
second one:
when multiplying exponents, you add with like
so if you multipliy
x^2yz^3 times x^4y^2z^2 thne you would get x^6y^3z^5
when multiply with coeficients
2x^2yz^3 times 4x^4y^2z^2=8x^6y^3z^5
so using associative property a(bc)=(ab)c
2/3 times p^4 times y^3 times y^4 times s^5 times 6 times p^2 times s^3
group like terms
(2/3 times 6) times (p^4 times p^2) times (y^3 times y^4) times (s^5 times s^3)
(4) times (p^6) times (y^7) times (s^8)
4p^6y^7s^8