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2 years ago

Find the measure of <7

Mathematics

1 answer:

Montano1993 [528]2 years ago

8 0

Hey there! :D

Vertical angles are congruent, they have the same measure.

So, <7 and <5 are vertical angles. They share the same vertex, and if you were to draw a straight line between them, it would connect and bisect them both equally.

<5= 45, so <7= 45.

I hope this helps!
~kaikers

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The forumal below is used to convert a temputure in degrees celsius, C, to a tempurturein degrees fahrenheit, F.

Vika [28.1K]

Answer:

59 F

Step-by-step explanation:

F=1.8C+32

Let C = 15

F = 1.8 (15) +32

Multiply 1.8 times 15

F = 27+32

F = 59

15 degrees C is 59 degrees F

5 0

2 years ago

A recent study of 26 city residents showed that the time they had lived at their present address has a mean of 10.3 years with t

svetlana [45]

Answer:

The 95% confidence interval is $9.15< \mu < 11.45$

Step-by-step explanation:

From the question we are told that

The sample size is n = 26

The mean is $\= x = 10.3$

The standard deviation is $s = 3$

From the question we are told the confidence level is 95% , hence the level of significance is

$\alpha = (100 - 95 ) \%$

=> $\alpha = 0.05$

Generally from the normal distribution table the critical value of $\frac{\alpha }{2}$ is

$Z_{\frac{\alpha }{2} } = 1.96$

Generally the margin of error is mathematically represented as

$E = Z_{\frac{\alpha }{2} } * \frac{\sigma }{\sqrt{n} }$

=> $E = 1.96 * \frac{3}{\sqrt{26} }$

=> $E = 1.1532$

Generally 95% confidence interval is mathematically represented as

$\= x -E < \mu < \=x +E$

=> $10.3 -1.1532 < \mu < 10.3 + 1.1532$

=> $9.15< \mu < 11.45$

7 0

2 years ago

A garrison of 400men had food for 40days.After 10 days,200 more men joined them .How long will the food last now?(Assume that th

mestny [16]

Let $x$ be the amount of food needed for one man for one day. At the beginning, we have enough food for 400 men for 40 days, i.e.

$400\cdot 40\cdot x = 16000x$

After 10 days, the 400 men will have consumed

$400\cdot 10\cdot x = 4000x$

food, impliying that the food remaining is

$16000x-4000x=12000x$

If 200 more men join the garrison, there are now 600 men. Each of them requires $x$ food each day, and there are $12000x$ units of food remaining. They will last