Answer:
P(B|A)=0.25 , P(A|B) =0.5
Step-by-step explanation:
The question provides the following data:
P(A)= 0.8
P(B)= 0.4
P(A∩B) = 0.2
Since the question does not mention which of the conditional probabilities need to be found out, I will show the working to calculate both of them.
To calculate the probability that event B will occur given that A has already occurred (P(B|A) is read as the probability of event B given A) can be calculated as:
P(B|A) = P(A∩B)/P(A)
= (0.2) / (0.8)
P(B|A)=0.25
To calculate the probability that event A will occur given that B has already occurred (P(A|B) is read as the probability of event A given B) can be calculated as:
P(A|B) = P(A∩B)/P(B)
= (0.2)/(0.4)
P(A|B) =0.5
Answer:
(x-1)(x+9) or x^2 + 8x-9, if you simplify.
Step-by-step explanation:
Answer:
6 sets
Step-by-step explanation:
(“of”=multiply)
Step 1.
1/5 of 45 sets = 45 x 1/5 = 9 sets.
Step2.
2/3 of 9 sets = 9 x 2/3 = 6 sets
Final Answer:
6 sets
I think it would be the first
