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3 years ago

What is 12.1, 12.34, 12.43 and 12.5 from greatest to least?

Mathematics

1 answer:

ratelena [41]3 years ago

7 0

12.5, 12.43, 12.34, 12.1 from greatest to least.

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HELP ASAP 15 POINTS!!! What is the solution to this equation? 6(x-5)=4x+20

Andre45 [30]

Answer:

Step-by-step explanation:

What is the solution to this equation?

6 * (x - 5) = 4x + 20

6x - 30 = 4x + 20

2x = 20 + 30

2x = 50

x = 50 : 2

x = 25

-------------------

check

6 * ( 25 - 5) = 4 * 25 + 20

6 * 20 = 100 + 20

120 = 120

the answer is good

3 0

1 year ago

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What is it plz answer

Masteriza [31]

The answer is the second one

7 0

2 years ago

48 = 4t + 12 How would I solve this someone please respond fast.

raketka [301]

Answer:

t=9

Step-by-step explanation:

Move all terms that don't contain

t to the right side and solve.t=9

8 0

2 years ago

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Use mathematical induction to prove the statement is true for all positive integers n, or show why it is false:

kondaur [170]

$\text{Proof by induction:}$
$\text{Test that the statement holds or n = 1}$

$LHS = (3 - 2)^{2} = 1$
$RHS = \frac{6 - 4}{2} = \frac{2}{2} = 1 = LHS$
$\text{Thus, the statement holds for the base case.}$

$\text{Assume the statement holds for some arbitrary term, n= k}$
$1^{2} + 4^{2} + 7^{2} + ... + (3k - 2)^{2} = \frac{k(6k^{2} - 3k - 1)}{2}$

$\text{Prove it is true for n = k + 1}$
$RTP: 1^{2} + 4^{2} + 7^{2} + ... + [3(k + 1) - 2]^{2} = \frac{(k + 1)[6(k + 1)^{2} - 3(k + 1) - 1]}{2} = \frac{(k + 1)[6k^{2} + 9k + 2]}{2}$

$LHS = \underbrace{1^{2} + 4^{2} + 7^{2} + ... + (3k - 2)^{2}}_{\frac{k(6k^{2} - 3k - 1)}{2}} + [3(k + 1) - 2]^{2}$
$= \frac{k(6k^{2} - 3k - 1)}{2} + [3(k + 1) - 2]^{2}$
$= \frac{k(6k^{2} - 3k - 1) + 2[3(k + 1) - 2]^{2}}{2}$
$= \frac{k(6k^{2} - 3k - 1) + 2(3k + 1)^{2}}{2}$
$= \frac{k(6k^{2} - 3k - 1) + 18k^{2} + 12k + 2}{2}$
$= \frac{k(6k^{2} - 3k - 1 + 18k + 12) + 2}{2}$
$= \frac{k(6k^{2} + 15k + 11) + 2}{}$
$= \frac{(k + 1)[6k^{2} + 9k + 2]}{2}$
$= \frac{(k + 1)[6(k + 1)^{2} - 3(k + 1) - 1]}{2}$
$= RHS$

Since it is true for n = 1, n = k, and n = k + 1, by the principles of mathematical induction, it is true for all positive values of n.

3 0

3 years ago

Multiply 58x7. Enter your answers in the boxes to complete the area model, 7 58 x 7 =

zubka84 [21]

Answer:

$7 \times 58 = 406$

8 0

2 years ago

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