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V125BC [204]
3 years ago
8

Jill entered y=2*5^(x−4)y=2*5^(x−4) into an online graphing tool. What function did she graph? y=2(5)x−4y=2(5)x−4y=(2⋅5)x−4y=(2⋅

5)x−4y=(2⋅5)x−4y=(2⋅5)x−4y=2(5)x−4
Mathematics
1 answer:
dusya [7]3 years ago
5 0
The answer to your question is A. 2*5^{x-4} . I hope that this is the answer that you were looking for and it has helped you.
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Please help!<br> And explain the answers too!
RideAnS [48]
1) He worked 4 hours leaving 6 more hours for him.
rate for A alone 6 baker
rate for A & B together 4
1/a+1/b=1/x
1/6+1/b=1/4
1/b=1/4-1/6
1/b=6/24-4/24
1/b=2/24
1/b=1/12
b=12
rate for wife alone 12 hours for the remaining 6 hours
check
1/6+1/12=1/4
12/72+6/72=1/4
18/72=1/4
ok
codewa
But we want to know how long it would have taken her for the whole job not just part of it
he works twice as fast as she does so the job that takes him 10 hours alone would take her 20 hours alone.

2) jessica and cynthia work in a pet shop.
it takes jessica 6 hours to groom all the pets but cynthia needs 8 hours to groom them.
if jessica starts to groom 1 hour before cynthia joins, how long will it take them to finish?
:
let t = time it takes them to finish (C's working time)
then
t+1 = J's working time
let 1 = completed job (all pets groomed)
:
A shared work equation, each does a fraction of the job, the two fractions add up to 1
%28%28t%2B1%29%29%2F6 + t%2F8 = 1
Multiply by the least common multiple of 6 and 8, 24. cancel the denominators
4(t+1) + 3t = 24
4t + 4 + 3t = 24
4t + 3t = 24 - 4
7t = 20
t = 20/7
t = 26%2F7 hrs, which is: 2 + 6%2F7*60 = 2 hrs 51.43 min to finish the job

3) math club takes 40 minutes
science takes 50 minutes.
rate * time = quantity
quantity = 1 set up of the tables.
rate for math club is 1/40 of all the tables in 1 minute.
rate for science club is 1/50 of all the tables in 1 minute.
math club works for 10 minutes.
rate * time = quantity
1/40 * 10 = 10/40 = 1/4 of the tables are already set up by the math club.
there are 3/4 of the tables that still need to be set up.
rate * time = quantity
the rates of the math club and the science club are additive.
(1/40 + 1/50) * time = 3/4 of the tables that still need to be set up.
common denominator is 200.
(5/200 + 4/200) * time = 3/4.
9/200 * time = 3/4
time = 3/4 * 200/9 = 600 / 36 = 16 and 2/3 minutes.
total time required is 10 + 16 + 2/3 minutes = 26 + 2/3 minutes.
how to check.
10 minutes is used to do 1/4 of the tables.
16 + 2/3 minutes is used to do the remaining 3/4 of the tables.
combined rate of math and science club is 9/200 of the tables in 1 minute.
math club rate of 1/40 * 10 = 10/40 = 1/4 of the tables.
combine rate of 9/200 * (16 + 2/3) = 9/200 * 50/3 = 450/600 = 9/12 = 3/4 of the tables.
1/4 + 3/4 = 1 = all of the tables.

6 0
2 years ago
Find the equation of the line
Valentin [98]

Answer:

y=-5x+1

Step-by-step explanation:

m=15-5/-6+4\\m=10/-2\\m=-5\\y=-5x+b\\x=4, y=5\\5=1(4)+b\\5=4+b\\5-4=b\\b=1\\y=-5x+1

7 0
3 years ago
Which if of the following is not true.
guapka [62]

Answer:

It will be the last one

Step-by-step explanation:

This is because the slope for AB is 1/3 while BC is 2/3

Hope this Helped

6 0
3 years ago
Use the formula for interest P=750 r=7% Y=25 A=?
Over [174]

Answer:

2062.50

Step-by-step explanation:

Interest = (Principle x rate x time)/100

Amount = Principle + interest

Principle = 750

Rate = 7%

Time = 25 years

(750 x 7 x 25)/100

= 131250/100

=1312.50

Principle = 750

Interest = 1312.50

Amount = 750 + 1312.50

Amount = 2062.50

7 0
3 years ago
Multiply (x-1)(x³+4x²+4x-1) and combine like terms. Explain how you reached your answer.
Hitman42 [59]

Answer:

x⁴+3x³ -5x +1

Step-by-step explanation:

To multiply this we are going to <u>multiply each term of the binomial by each term of the polynomial.</u>

(x-1)(x^{3}+4x^{2}  +4x-1)\\=x^4+4x^3+4x^2-x -x^3-4x^2-4x+1

Now we are going to <u>combine like terms (this means we are going to sum up terms with the same exponent)</u>

x^4+4x^3+4x^2-x -x^3-4x^2-4x+1 = x^4 +(4x^3-x^3)+(4x^2-4x^2)+(-x-4x)+1\\=x^4+3x^3-5x+1

Thus, the answer is x⁴+3x³ -5x +1

5 0
3 years ago
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