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inysia [295]
3 years ago
11

What is 41/19 to the nearest tenth

Mathematics
2 answers:
olga2289 [7]3 years ago
6 0

Answer:

2.2

Step-by-step explanation:

41/9 is 2.15789473684

since you need it to the nearest tenth, just get rid of the other numbers past the five, you will then have 2.15

since you are looking for the nearest tenth, you need to look at the 2nd number after the decimal place to determine whether it rounds up or down. ( a helpful rule is 5 or above, give it a shove. 4 or below, leave it alone. because the 2nd digit is 5 you need to give the 1 a shove and turn it into a 2. Since you gave the 5 a shove, you need to get rid of that 2nd digit in your answer.

FINAL ANSWER: 2.2

harkovskaia [24]3 years ago
3 0

Answer:

41.20 or 41.2

Step-by-step explanation:

when you round it to the tenths place you get 20 instead of 19 so therefore it is 41.20 or 41.2

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A rhombus ABCD has AB = 10 and m∠A = 60°. Find the lengths of the diagonals of ABCD.
melisa1 [442]
Three important properties of the diagonals of a rhombus that we need for this problem are:
1. the diagonals of a rhombus bisect each other
2. the diagonals form two perpendicular lines
3. the diagonals bisect the angles of the rhombus

First, we can let O be the point where the two diagonals intersect (as shown in the attached image). Using the properties listed above, we can conclude that ∠AOB is equal to 90° and ∠BAO = 60/2 = 30°. 

Since a triangle's interior angles have a sum of 180°, then we have ∠ABO = 180 - 90 - 30 = 60°. This shows that the ΔAOB is a 30-60-90 triangle.

For a 30-60-90 triangle, the ratio of the sides facing the corresponding anges is 1:√3:2. So, since we know that AB = 10, we can compute for the rest of the sides.

\overline{OB}:\overline{AB} = 1:2
\overline {OB}:10 = 1:2
\overline{OB} = \frac{1}{2}(10) = 5

Similarly, we have

\overline{AO}:\overline{AB} = \sqrt{3}:2
\overline {AO}:10 = \sqrt{3}:2
\overline{AO} = \frac{\sqrt{3}}{2}(10) = 5\sqrt{3}

Now, to find the lengths of the diagonals, 

\overline{AD} = 2(\overline{AO}) = 10\sqrt{3}
\overline{BC} = 2(\overline{OB}) = 10

So, the lengths of the diagonals are 10 and 10√3.

Answer: 10 and 10√3 units

8 0
3 years ago
Solve the equation.
Levart [38]

Answer:

x=34

Step-by-step explanation:

6 - ( x-7) ^ 1/3 = 3

Subtract 6 from each side

6-6 - ( x-7) ^ 1/3 = 3-6

- ( x-7) ^ 1/3 = -3

Divide each side by a negative

 ( x-7) ^ 1/3 = 3

Cube each side

 ( x-7) ^ 1/3 ^3 = (3)^3

x-7 = 27

Add 7 to each side

x-7+7 = 27+7

x = 34

Check

6 - ( 34-7) ^ 1/3 = 3

6 - (27^1/3 = 3

6 -3 =3

3=3

Good solution

8 0
3 years ago
List the term(s) in the following expression:<br> 2x2–5xy + 8y4
eduard

Answer:

8

y

4

+

2

x

2

−

5

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y

Step-by-step explanation:

3 0
3 years ago
Scientist are studying a bacteria sample. The function f(x)=360(1.07)^x gives the number of bacteria in the sample at the end of
Lapatulllka [165]

Options :

A. The initial number of bacteria is 7.

B. The initial of bacteria decreases at a rate of 93% each day.

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Answer:

C. The number of bacteria increases at a rate of 7% each day.

Step-by-step explanation:

Given the function :

f(x)=360(1.07)^x ; Number of bacteria in sample at the end of x days :

The function above represents an exponential growth function :

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Where A = initial amount ;

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x = time

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A = initial amount of bacteria = 360

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1 + r = 1.07

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