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anastassius [24]
2 years ago
11

Determine whether the graphs of the given equations are​ parallel, perpendicular, or neither.

Mathematics
1 answer:
12345 [234]2 years ago
3 0

Answer:

A. Perpendicular

CarryOnLearning

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What is the term-to-term rule for this sequence?<br> 64, 32, 16, 8, 4
just olya [345]

Answer:

a n=1/2 an - 1

Step-by-step explanation:

64,32,16,8,4. is a geometric sequence. this is a sequence where, to get from one term to the next, there is a number that you have to multiply it by. this is the same for all parts of the sequence.

4 0
3 years ago
Two athletic teams play a series of games; the first team to win 4 games is declared the overall winner. Suppose that one of the
kodGreya [7K]

Answer:

  • p=0.7103 (4-game series)
  • p=0.6480 (2-game series)

Step-by-step explanation:

Let X be the random variable equal the the first 4 straight wins. An overall win for the stronger team implies a negative binomial function with the parameters  n=4, p=0.6:

P(X=4)={{i-1}\choose {4-1}}0.6^40.4^{i-4},\  i=4,5,6,7

#We find probabilities for the different values of i:

P(X=4)={3\choose 3}0.6^4=0.1296\\\\P(X=5)={4\choose 3}0.6^40.4^1=0.2074\\\\P(X=6)={5\choose 3}0.6^40.4^2=0.2074\\\\P(X=4)={6\choose 3}0.6^40.4^3=0.1659

Hence, probability of the stronger team winning overall is:

=P(X=4)+P(X=5)+P(X=6)+P(X=7)\\\\=0.7103

#Define Y as the random variable for winning 2/3 games.:

P(Y=2)={1\choose 1}0.6^2=0.3600\\\\P(Y=3)={2\choose3}0.6^20.4=0.2880\\\\P(win)=0.2880+0.3600=0.6480

Hence, probability of the stronger team winning in 2 out 3 game series is 0.6480

The stronger team has a higher chance of winning in a 4-game series(0.7103>0.6480)

8 0
3 years ago
Simplify.[2 × (10 + 5)] - 5
N76 [4]
2(10+5)−5 =(2)(15)−5 =30−5 =25 C is the answer.
4 0
3 years ago
Read 2 more answers
The distances of a port from 20 differ- ent locations form an AP. If the farthest distance is 300 km, and the nearest distance i
Mkey [24]

Answer:

Required difference = 270/19 km

Step-by-step explanation:

If we consider the AP of distances to be

a, a + r, a + 2r, ..., a + 19r,

where a is the distance of the nearest location from the port and r is the difference between any two successive location.

Given that,

a + 19r = 300 .....(1)

a = 30 ..... (2)

Using (2), from (1), we get

30 + 19r = 300

or, 19r = 300 - 30

or, 19r = 270

or, r = 270/19

Therefore the distance between any two successive location is 270/19 km.

5 0
2 years ago
It’s really easy but I don’t know the steps can someone help?
tigry1 [53]

Answer:

x=0

Step-by-step explanation:

1/2(40+2x)=20

20+x=20

x=0

(I believe that s is the bisector, please correct me if I am wrong)

3 0
2 years ago
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