Answer:
Step-by-step explanation:
For #6;
We know that there are 46% male students and 30% of them are seniors. This means that we have to assume that 30% of the male students are seniors and that 30% of the female students are seniors. Taking 30% of 46% gives us 13.8%.
For #7;
We are looking for the possibility that we choose a junior student (22%) or a sophomore student (28%). This adds up to 50% (22%+28% = 50%). That is out answer.
Answer:
Step-by-step explanation:
Write a list of all possible outcomes
1-2
1-3
1-4
2-1
2-3
2-4
3-1
3-2
3-4
4-1
4-2
4-3
There are 12 possible outcomes. How many of them have totals of 6 or 7
I count 4
So the probability is 4/12 = 1/3, just as you said.
Is there an easier way?
You might be able to get the 12 easier.
You have 4 choices for the first number and 3 for the second.
P(12) = 4*3 = 12
Getting 6 or 7 might be somewhat trickier.
4 and 3 make seven. That gives two ways 4-3 and 3-4
4 and 2 make six. That gives 2 more ways 4-2 and 2-4
That's all that's possible.
answer: 4 ways make success. The total number of ways is 12.
The most likely number of cats = 21/37 x 8 = 4.54 ≈ 5 cats
The most likely number of dogs = 16/37 x 8 = 3.46 ≈ 3 dogs
The probability of that arrangement happening = 1/8^2 = 1/64 = 0.00156
