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Gnesinka [82]
3 years ago
15

Solve 1n(5x+7) = 8. Round to the nearest thousandth. Show your work. Can anyone help me? I can't seem to figure this one out!

Mathematics
1 answer:
iogann1982 [59]3 years ago
8 0

 (1): "c0"   was replaced by   "c^0". 

(2): Dot was discarded near "1.j". 1 more similar replacement(s)

Unauthorized use of the imaginary unit "i" or syntax error in complex arithmetic expression

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The solution to an inequality is 5≤x<9. What is the smallest value of x that will make the original inequality true?
Strike441 [17]

Answer:

5

Step-by-step explanation:

It is given that the solution to an inequality is

5\leq x

It means the original inequality is true for any values of x which is greater than or equal to 5 and less than 9.

We need to find the smallest value of x that will make the original inequality true.

5\leq x\text{ and }x

Therefore, smallest value of x is 5 that will make the original inequality true.

7 0
4 years ago
Work out m and c for the line y=2x+1​
Harman [31]

Answer:

Again... <em>m</em> = 2, and <em>c</em> = 1

8 0
3 years ago
Can some one help me solve this ?
kondaur [170]
<h2><u><em>The answer is d.</em></u></h2>

v = lwh

v/lh = lwh/lh

w = v/lh


5 0
3 years ago
What is the correct solution to the equation? 5(x - 5) = 15
Sloan [31]
C. 8

You substitute 8 into x, which makes the equation 5(8-5) = 15. 8-5 is 3, and 5 x 3 = 15.
7 0
4 years ago
Can someone plz help me solve this problem I need help plz someone help me!
cestrela7 [59]

Answer:   25 < P < 36

              15/4 < w < 26/4

              35/4 < L < 46/4

<u>Step-by-step explanation:</u>

Perimeter is BETWEEN 25 and 36

           25 <    P    < 36

Graph:  O--------------O

            25              36

Perimeter = 2L + 2w  ; substitute L = w + 5        

             25 < 2(w + 5) + 2w < 36

             25 < 2w + 10  + 2w < 36

              25 <  4w + 10          < 36

               15 <           4w         < 26

               \dfrac{15}{4} <             w         < \dfrac{26}{4}

              3\dfrac{3}{4}  <              w        <  6\dfrac{1}{2}

Graph:     O------------------------O

              3\dfrac{3}{4}                             6\dfrac{1}{2}

Perimeter = 2L + 2w  ; L = w + 5   --> w = L - 5      

             25 < 2L + 2(L - 5)  < 36

             25 < 2L + 2L  - 10 < 36

              25 <  4L - 10        < 36

              35 <           4L      < 46

              \dfrac{35}{4} <             L       < \dfrac{46}{4}

              8\dfrac{3}{4}  <            L      <  11\dfrac{1}{2}

Graph:     O------------------------O

               8\dfrac{3}{4}                          11\dfrac{1}{2}

Note: Make sure you use OPEN dots when graphing.

5 0
4 years ago
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