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pashok25 [27]
2 years ago
10

Given log630 ≈ 1.898 and log62 ≈ 0.387, log615 =

Mathematics
2 answers:
Tom [10]2 years ago
6 0

\log_630\approx1.898\\\\\log_62\approx0.387\\\\\log_615=\log_6\dfrac{30}{2}=\log_630-\log_62\approx1.898-0.387=1.511\\\\Used:\\\\\log_ab-\log_ac=\log_a\dfrac{b}{c}

Oksi-84 [34.3K]2 years ago
4 0

Answer:

The value of log_6{15} is 1.511.

Step-by-step explanation:

It is given that log_6{30}\approx 1.898 and log_6{2}\approx 0.387.

We have to find the value of log_6{15}.

It can be written as

log_6{15}=log_6\frac{30}{2}

Using property of lo, we get

log_6{15}=log_630-log_62          log_m\frac{a}{b}=log_ma-log_mb

Substitute log_6{30}\approx 1.898 and log_6{2}\approx 0.387 in the above equation.

log_6{15}=1.898-0.387

log_6{15}=1.511

Therefore the value of log_6{15} is 1.511.

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Answer:

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Step-by-step explanation:

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Answer:

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