1. Create a graph of the pH function. Locate on your graph where the pH value is 0 and where it is 1. You may need to zoom in on your graph.
<span>The pH value is 1 at the orange dot, and is 1 at the red dot. </span>
<span>The transformation p(t+1) results in a y-intercept. </span>
<span>In this graph, the blue line is the original and first parent function p(t) = –log10 t. The pink line represent p(t) + 1, the transformation shifts up the y-axis by 1, but the p(t) + 1 transformation does not result in a y-intercept like the ones prior. The gold line represents p(t +1), which shifts horizontally by 1 to the left. This does result in a y-intercept, because the graph doesn't completely flip over the line to the other side, and the green line represents -1*p(t), which causes the graph to flip upside down, and doesn't end up as a y- intercept.</span>
Answer:
The statement of the fundamental theorem of calculus shows the upper limit of the integral as exactly the variable of differentiation. Using the chain rule in combination with the fundamental theorem of calculus we may find derivatives of integrals for which one or the other limit of integration is a function of the variable of differentiation.
Step-by-step explanation:
Answer:
Step-by-step explanation:
Given is a Differential equation as
To bring it to linear form we can divide the full equation by x
This is of the form
y'+p(x) *y = q(x)
p(x) = 1/x
So find
Solution is
Use the initial value as y(e) =1
So solution is
Answer:
area of a circle πr^2
r = 10/2 r = 5
π5^2 = 78.5
area of the square length X width
7 x 7 = 49
78.5 - 49 = 29.5
shaded region = 29.5 square cm
