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shtirl [24]
3 years ago
15

An odd number between 301 and 370 has three different digits. If the sum of its digits is five times the hundreds digit, find th

e number. Show your work.
Mathematics
1 answer:
damaskus [11]3 years ago
5 0
For the answer to the question above, <span> 
5x3 (the hundreds digit)= 15
so 3+x+y=15. 15-3=12. x+y=12.
No even number + odd number can be = 12, so both digits must be odd.
That leaves us with 3+3+z=15, 3+3+x =15 and 3+5+y= 15. 3+1+9 (highest odd digit)= 13 so that is wrong.
3+3+9= 15, but there is a double digit, so wrong again. 3+5+7=15. 357 is the answer.</span>
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Given

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\Rightarrow M\left(k(x)\right)=3(2x+3)^2+7(2x+3)-10\\\Rightarrow M\left(k(x)\right)=3(4x^2+9+12x)+14x+21-10\\\Rightarrow M\left(k(x)\right)=12x^2+50x+38

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Giving Brainiest ~~ :)
Gre4nikov [31]
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