Question

Distribute 9(3x^3-2)

Answer 1

First you need to distribute the 9.

So 9 times 3 and 9 times 2

The Algebraic should look like now: (27^3x-18)

So the final answer is: $27x^{3} - 18$

You cannot simplify it anymore because there are no like terms left.

Answer 2

first you have multiply 9 time all inside the parethesys.

9 time 3= 27

9 time -2=18

the 9 doesn't affect the exponent 3

27x^3-18