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2 years ago

15

I need help with this can you explain how to do this so I can understand please ASAP!!

1 answer:

Ratling [72]2 years ago

7 0

Answer: 1.64 2.100

Step-by-step explanation:

The reason for this is squaring something is simply mulyiplying the number by itself. for example

8 squared

there is a 2 above the 8 which means we will do 8x8.

8x8= 64

Hope this helps!!!!

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I really don't get this type of math so can someone please help me with this thank you

solmaris [256]

The area for a trapezoid is A=1/2(b*1+b*2)h
Your base is your two parallel sides, and your parallel sides in this case is 5cm and 11cm, so that means your bases are 5&11. Your height is 4.
A=1/2(5+11)4
In order to do this you need to do the distributive property first.
1/2 x 5 = 2 1/2
1/2 x 11 = 5 1/2
Then next you need to do:
2 1/2 + 5 1/2 = 8
The last step is to do:
8 x 4 = 32
SO THE ANSWER IS 32.

5 0

3 years ago

Show work! my teacher told me this was wrong, what's the correct answer?

Studentka2010 [4]

Answer:

it is Ahmed shoevked more your calculations are wrong

7 0

2 years ago

1/2x + 1/4y = 3 solve for y

Liono4ka [1.6K]

Answer:

y=-2x+12

Step-by-step explanation:

First, subtract 1/2 from each side

1/4y = -1/2x + 3 --> multiply each side by 4

y = -2x + 12 is your final answer

5 0

2 years ago

What is the cube root of -256<br> please show steps and keep answer in radical form and not decimals

polet [3.4K]

Answer:

-4∛4

Step-by-step explanation:

Simplify the radical expression

-∛256→ -2²x∛2²

then evaluate the power

-4∛4

It would be greatly appreciated if you gave me brainiest

7 0

2 years ago

Read 2 more answers

Write the equation for a 3rd degree polynomial function that has roots at x = 1–3i and x = 2. The y‑intercept is (0,10). Write a

HACTEHA [7]

Answer:

$\displaystyle P(x)=-\frac{1}{2}(x^2+2x+10)(x-2)$

Step-by-step explanation:

<u>Factored Form Of Polynomials </u>

If we know the roots of a polynomial as

$\alpha _1,\alpha _2,\alpha _3$

the polynomial can be expressed in factored form as

$a(x-\alpha _1)(x-\alpha _2)(x-\alpha _3)$

We are given two of the three roots of the polynomial:

$\alpha _1=1-3i$

$\alpha _2=2$

The other root must be the conjugate of the complex root:

$\alpha _3=1+3i$

Recall the product of two complex conjugate numbers is

$(1-3i)(1+3i)=1^2-(3i)^2=1+9=10$

The required polynomial is

$P(x)=a\left[ x-(1-3i)\right ]\left[ x-(1+3i)\right ](x-2)$

$P(x)=a(x^2+2x+10)(x-2)$

This is the factored form of the polynomial where only real numbers appear

We need to find the value of a, such as

$P(0)=10$

$P(0)=a(0^2+2(0)+10)(0-2)=10$

$-20a=10$

Thus the value of a is

$\displaystyle a=-\frac{1}{2}$

The expression of the required polynomial is

$\boxed{P(x)=-\frac{1}{2}(x^2+2x+10)(x-2)}$

5 0

2 years ago