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Nat2105 [25]
3 years ago
14

Write a quadratic equation whose solutions are 7i and -7i

Mathematics
1 answer:
aliya0001 [1]3 years ago
4 0
Because -7i and 7i are the solutions to the quadratic equation, you can first write it in factored form (x-7i)(x+7i). The you multiply this out and get x^{2} +49.
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Multiply or divide as indicated.
Rainbow [258]
5a^2 * 6a^4

=
5*6 * a^(2+4)

so that's a 
30a^6
8 0
3 years ago
Jose burns an average of 200 calories in 25 minutes of running. Does Jose burn more than 500 calories per hour
Bogdan [553]
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4 0
3 years ago
1. Find the area of the region bounded above by y = e^x, bounded below by y = x, and bounded on the sides
salantis [7]

The area of the region bounded above by y= eˣ bounded by y = x, and bounded on the sides; x =0; and x = 1 is given as e¹ - 1.5.

<h3>What is the significance of "Area under the curve"?</h3>

This is the condition in which one process increases a quantity at a certain rate and another process decreases the same quantity at the same rate, and the "area" (actually the integral of the difference between those two rates integrated over a given period of time) is the accumulated effect of those two processes.

<h3>What is the justification for the above answer?</h3>

Area = \int\limits^1_0 {(e^x-x)} \, dx

= \int\limits^1_0 {e^x-x} \, dx - \int\limits^1_0 {(x)} \, dx

= e¹-(1/2-0); or

Area = e -1.5 Squared Unit

The related Graph is attached accordingly.

Learn more about area bounded by curve:
brainly.com/question/27866606
#SPJ1

3 0
2 years ago
First, if the altitude drawn to the hypotenuse of a right triangle divides the hypotenuse into two segments with lengths of 9 in
Serhud [2]
A right triangle base in your question, its hypotenuse is divided in to two line segment by a line of altitude and those segment are measured as 9 inches and 17 inches, so base on my calculation the exact length of the altitude is 3*sqrt(17)
8 0
3 years ago
Solve problem y+7=-9​
Delvig [45]

Answer:  -16

Step-by-step explanation:

y + 7 = -9

-9 - 7 = -16

-16 + 7 = -9

8 0
4 years ago
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