The answer is 6 as if you plug in 6 in the denominator (6)-6 is 0 which makes the fraction undefined
Answer:
B.
Step-by-step explanation:
Answer:
x=-1-5√17/2
Step-by-step explanation:
logo((x-2)(x+2))=2
logo(x²+3x-2x-6)=2
x²+3x-2x-6=10²
x²+x-6=100
x²+x-106=0
x=-1+5√17/2
Well this is simple a calculator type problem...but if you are curious as the the algorithm used by simple calculators and such...
They use a Newtonian approximation until it surpasses the precision level of the calculator or computer program..
A newtonian approximation is an interative process that gets closer and closer to the actual answer to any mathematical problem...it is of the form:
x-(f(x)/(df/dx))
In a square root problem you wish to know:
x=√n where x is the root and n is the number
x^2=n
x^2-n=0
So f(x)=x^2-n and df/dx=2x so using the definition of the newton approximation you have:
x-((x^2-n)/(2x)) which simplifies further to:
(2x^2-x^2+n)/(2x)
(x^2+n)/(2x), where you can choose any starting value of x that you desire (though convergence to an exact (if possible) solution will be swifter the closer xi is to the actual value x)
In this case the number, n=95.54, so a decent starting value for x would be 10.
Using this initial x in (x^2+95.54)/(2x) will result in the following iterative sequence of x.
10, 9.777, 9.774457, 9.7744565, 9.7744565066299210578124802523397
The calculator result for my calc is: 9.7744565066299210578124802523381
So you see how accurate the newton method is in just a few iterations. :P
Answer:
B: II, IV, I, III
Step-by-step explanation:
We believe the proof <em>statement — reason</em> pairs need to be ordered as shown below
Point F is a midpoint of Line segment AB Point E is a midpoint of Line segment AC — given
Draw Line segment BE Draw Line segment FC — by Construction
Point G is the point of intersection between Line segment BE and Line segment FC — Intersecting Lines Postulate
Draw Line segment AG — by Construction
Point D is the point of intersection between Line segment AG and Line segment BC — Intersecting Lines Postulate
Point H lies on Line segment AG such that Line segment AG ≅ Line segment GH — by Construction
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II Line segment FG is parallel to line segment BH and Line segment GE is parallel to line segment HC — Midsegment Theorem
IV Line segment GC is parallel to line segment BH and Line segment BG is parallel to line segment HC — Substitution
I BGCH is a parallelogram — Properties of a Parallelogram (opposite sides are parallel)
III Line segment BD ≅ Line segment DC — Properties of a Parallelogram (diagonals bisect each other)
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Line segment AD is a median Definition of a Median
