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Akimi4 [234]
3 years ago
7

John has 28 cards. He gives his friend Timmy 10 cards and gave the rest to his brother. Then he gained 10 cards and

Mathematics
2 answers:
arsen [322]3 years ago
8 0

Answer:

7 cards

Step-by-step explanation:

Well if John started off with 28 and gave away 10,

28-10=18

Gave tthe last 18 to his brother

18-18 = 0

Gained 10

0+10=10

Lost 3

10-3=7

Hence, John has 7 cards left.

hichkok12 [17]3 years ago
4 0
He has 7 cards left since,


He had 28

gave away 10 so, 28 - 10 = 18


he was left with 18 and gave the rest which is (18) to his brother

Now he has 0

but then he gained 10


he lost 3 so 10 - 3 = 7

So, he has 7 cards now

Hope this helps!!
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<span>Find an equation for the line parallel to 2y+4x = 8 and goes through the point (-3,3). Write your answer in the form y=mx+b.</span>
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kogti [31]

Answer:

\sqrt{3}


Step-by-step explanation:

We will be using 2 properties of radicals in this simplification (outlined below).

  • \sqrt{a*b}=\sqrt{a}* \sqrt{b}
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<em>Let's simplify this:</em>

2\sqrt{27} +\sqrt{12} -3\sqrt{3}-2\sqrt{12}\\ =2\sqrt{9*3}+\sqrt{4*3} -3\sqrt{3}-2\sqrt{4*3} \\=2\sqrt{9} \sqrt{3} +\sqrt{4} \sqrt{3}-3\sqrt{3}-2\sqrt{4} \sqrt{3} \\=2(3)\sqrt{3}+(2)\sqrt{3} -3\sqrt{3}-2(2)\sqrt{3} \\ =6\sqrt{3} +2\sqrt{3}-3\sqrt{3}-4\sqrt{3}  \\=\sqrt{3}


First answer choice is right.

5 0
3 years ago
A.)12 <br> B.) 25<br> C.)51<br> D.) 77
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Answer:

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You are at a stall at a fair where you have to throw a ball at a target. There are two versions of the game. In the first
Tomtit [17]

Answer:

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And the probability of loss with the first wersion is 0.729

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And the probability of loss with the first wersion is 0.774

As we can see the best alternative is the first version since the probability of loss is lower than the probability of loss on version 2.

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Solution to the problem

Alternative 1

Let X the random variable of interest, on this case we now that:

X \sim Binom(n=3, p=0.1)

The probability mass function for the Binomial distribution is given as:

P(X)=(nCx)(p)^x (1-p)^{n-x}

Where (nCx) means combinatory and it's given by this formula:

nCx=\frac{n!}{(n-x)! x!}

We can find the probability of loss like this P(X=0) and if we find this probability we got this:

P(X=0)=(3C0)(0.1)^0 (1-0.1)^{3-0}=0.729

And the probability of loss with the first wersion is 0.729

Alternative 2

Let Y the random variable of interest, on this case we now that:

Y \sim Binom(n=5, p=0.05)

The probability mass function for the Binomial distribution is given as:

P(Y)=(nCy)(p)^y (1-p)^{n-y}

Where (nCx) means combinatory and it's given by this formula:

nCy=\frac{n!}{(n-y)! y!}

We can find the probability of loss like this P(Y=0) and if we find this probability we got this:

P(Y=0)=(5C0)(0.05)^0 (1-0.05)^{5-0}=0.774

And the probability of loss with the first wersion is 0.774

As we can see the best alternative is the first version since the probability of loss is lower than the probability of loss on version 2.

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(02.05 MC) A dance school has 63 ballet dancers. If 42% of the total number of dancers in the school are ballet dancers, what is
Elena L [17]

Alright, lets get started.

Suppose total number of dancers in school = x

We have given in question, 42 % of total dancers are ballet dancers.

So, we could find number of ballet dancers by finding 42 % of total dancers.

Number of ballet dancers = x * 42 %

Number of ballet dancers = x * 42/100 = 0.42 x

As per given in question, there are 63 ballet dancers in school.

Which means 0.42 x = 63

Dividing 0.42 from both sides

0.42 x / 0.42 = 63 / 0.42

x = 150

Hence number of total dancers in school = 150 : Answer

Hope it will help :)

4 0
3 years ago
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