Answer:
16
Step-by-step explanation:
Put the numbers where the variables are and evaluate:
F(3) = 2(3)^2 +1 = 19
G(4) = 2(4) -1 = 7
H(5) = 5
Then the desired sum is ...
F(3) +G(4) -2H(5) = 19 +7 -2(5) = 16
Answer:
Step-by-step explanation:
The relevant rule of exponents is ...
(a^b·c^d)^e = a^(be)·c^(de)
Then ...
(m^(5/4)·n^(-4/5))^(7/3) = m^(5/4·7/3)·n^(-4/5·7/3)
= m^(35/12)·n^(-28/15)
__
Since you want positive rational exponents, you can write this as ...
= m^(35/12)/n^(28/15)
Answer:
1091750
Step-by-step explanation:
if your dividing
Answer: D) 10 jerseys
Step-by-step explanation:
Let j represent the number of jerseys and C for total cost
Local company eqn: C = 5.25j + 45
Online company eqn: C = 7.75j + 20
Set both sides equal to solve:
5.25j + 45 = 7.75j + 20
5.25j - 7.75j = 20 -45
- 2.5j = -25
j = 10
Therefore, the cost is the same for both companies when 10 jerseys are sold
To simplify the function, we need to know some basic identities involving exponents.
1. b^(ax)=(b^x)^a=(b^a)^x
2. b^(x/d) = (b^x)^(1/d) = ((b^(1/d)^x)
Now simplify f(x), where
f(x)=(1/3)*(81)^(3*x/4)
=(1/3)(3^4)^(3*x/4) [ 81=3^4 ]
=(1/3)(3^(4*3*x/4) [ rule 1 above ]
=(1/3) (3^(3*x)
=(1/3)(3^(3x)) [ or (1/3)(27^x), by rule 1 ]
(A) Initial value is the value of the function when x=0, i.e.
initial value
= f(0)
=(1/3)(3^(3x))
=(1/3)(3^(3*0))
=(1/3)(3^0)
=(1/3)(1)
=1/3
(B) the simplified base base is 3 (or 27 if the other form is used)
(C) The domain for an exponential function is all real values ( - ∞ , + ∞ ).
(D) The range of an exponential function with a positive coefficient and without vertical shift is ( 0, + ∞ ).
