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Katarina [22]
4 years ago
4

Which line is perpendicular to a line that has a slope of Negative one-third?

Mathematics
2 answers:
Yanka [14]4 years ago
5 0

Answer:

line EF

Finding Perpendicular Lines

On a coordinate plane, 4 lines are shown. Line A B has points (negative 3, 2) and (3, 0). E F has points (0, negative 3) and (2, 3). Line J K has points (negative 3, negative 4) and (3, negative 2). Line M N has points (negative 1, 4) and (2, negative 5).

Which line is perpendicular to a line that has a slope

of Negative one-third?

Hitman42 [59]4 years ago
3 0

\huge\boxed{\text{Any line with a slope of 3}}

To find a line perpendicular to a line with a given slope, you just need to find the opposite reciprocal of the slope.

We are given a slope of -\frac{1}{3}.

Start by multiplying it by -1. This means that if it was a negative number, it would become positive, and vice versa.

-\frac{1}{3}*-1=\frac{1}{3}

Now, flip the numerator and denominator. This is called finding the reciprocal.

\frac{1}{3}\longrightarrow\frac{3}{1}=\boxed{3}

This means that any line with a slope of 3 would be a correct answer.

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Given:

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To find:

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Solution:

We have,

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It is an AP because the difference between two consecutive terms are same.

Here,

First term (a) = 25

Common difference (d) = 20-25

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The nth terms of an AP is

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Putting a=25, n=9 and d=-5 to get the 9th term.

a_9=25+(9-1)(-5)

a_9=25+(8)(-5)

a_9=25-40

a_9=-15

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