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2 years ago

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Write and equation and solve it

1 answer:

Vedmedyk [2.9K]2 years ago

6 0

Answer: he have saved $500? ... the question. Does your answer make sense? ... Solve the following problems and show all your work. (Remember to use the 5 steps for solving two-step equation word problems!) | 1. ... Joe went to the hobby shop and bought 2 model sports cars at $8.95 each and some paints.

Step-by-step explanation:

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Which of the following expression is equivalent to the expression below?

Nonamiya [84]

Use the distributive property on the given expression.

4(2x + 11) = 4 * 2x + 4 * 11 = 8x + 44

Only choice C shows the correct expression.

Answer: C. 8x + 44

4 0

2 years ago

Alice searches for her term paper in her filing cabinet, which has several drawers. She knows thatshe left her term paper in dra

katen-ka-za [31]

You made a mistake with the probability $p_{j}$ , which should be $p_{i}$ in the last expression, so to be clear I will state the expression again.

So we want to solve the following:

Conditioned on this event, show that the probability that her paper is in drawer $j$ , is given by:

(1) $\frac{p_{j} }{1-d_{i}p_{i} } , if j \neq i,$ and

(2) $\frac{p_{i} (1-d_{i} )}{1-d_{i}p_{i} } , if j = i.$

so we can say:

$A$ is the event that you search drawer $i$ and find nothing,

$B$ is the event that you search drawer $i$ and find the paper,

$C_{k}$ is the event that the paper is in drawer $k, k = 1, ..., n.$

this gives us:

$P(B) = P(B \cap C_{i} ) = P(C_{i})P(B | C_{i} ) = d_{i} p_{i}$

$P(A) = 1 - P(B) = 1 - d_{i} p_{i}$

Solution to Part (1):

if $j \neq i$ , then $P(A \cap C_{j} ) = P(C_{j} )$ ,

this means that

$P(C_{j} |A) = \frac{P(A \cap C_{j})}{P(A)} = \frac{P(C_{j} )}{P(A)} = \frac{p_{j} }{1-d_{i}p_{i} }$

as needed so part one is solved.

Solution to Part(2):

so we have now that if $j$ = $i$ , we get that:

$P(C_{j}|A ) = \frac{P(A \cap C_{j})}{P(A)}$

remember that:

$P(A|C_{j} ) = \frac{P(A \cap C_{j})}{P(C_{j})}$

this implies that:

$P(A \cap C_{j}) = P(C_{j}) \cdot P(A|C_{j}) = p_{i} (1-d_{i} )$

so we just need to combine the above relations to get:

$P(C_{j}|A) = \frac{p_{i} (1-d_{i} )}{1-d_{i}p_{i} }$

as needed so part two is solved.

8 0

2 years ago

Use the following statement to answer the question.

MariettaO [177]

Addition property of equality

6 0

2 years ago

James and Terry open a savings account that has a 2.75% annual interest rate, compounded monthly. They deposited $500 into the a

zhuklara [117]

Answer:

$275

Step-by-step explanation:

This is what I got:

You first <u>convert</u> 2.75% into 0.0275

You then <u>multiply</u> 500 x 0.0275 = 13.75

Finally you <u>multiply</u> 13.75 x 20 = 275

so the answer should be 275

5 0

2 years ago

Marianna Martinez sells copy paper to local schools. She earns a 13 percent straight commission on all sales . In November her s

faltersainse [42]

Answer:

13%=0.13

28540*0.13=3710.2

8 0

2 years ago