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Natalija [7]
3 years ago
10

The head of a nail is circular, as shown. The head of this nail has a diameter of 6 millimeters.

Mathematics
1 answer:
Tcecarenko [31]3 years ago
6 0

Answer:

its A

Step-by-step explanation:

Hope it helps

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West ridge highschool is holding an honor roll banquet. It costs $95 to rent the cafeteria plus $13 for each person attending th
Art [367]

Answer: C(x) = 13x +95​

Step-by-step explanation:

Here's the remainder of the question:

If C(x) represents the total cost and x represents the number of people attending the banquet, which equation shows the total cost? A C(x)=95x – 13 B C(x)=13x – 95 C C(x)=95x +13 D C(x)=13x +95​

Based on the information given in the question, the total cost will be:

= 95 + 13(x)

= 95 + 13x

Therefore, the correct answer will be C(x)=13x +95​

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3 years ago
How many two digit numbers are divisible by either 3 or 5?
agasfer [191]
There are 18 that are divisible by 5. 10, 15, 20, 25, 30, 35, 40, 45, 50, 55, 60, 65, 70, 75, 80, 85, 90, 95

now find which of those are divisible by 3 (divide the numbers by three and if its a whole number that works for example 30 divided by 3 is 10 so thats one) 


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3 years ago
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HELP PLEASE ILL GIVE YOU 15 POINTS THANK YOU
sasho [114]

Answer:

X Y

4. 2

8. 3

12. 4

hope this is helpful for you

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David found and factored out the GCF of the polynomial 80b4 – 32b2c3 + 48b4c. His work is below. GFC of 80, 32, and 48: 16 GCF o
BlackZzzverrR [31]

Answer: The correct statements are

The GCF of the coefficients is correct.

The variable c is not common to all terms, so a power of c should not have been factored out.

David applied the distributive property.

Step-by-step explanation:

GCF = Greatest common factor

1) GCF of coefficients : (80,32,48)

80 = 2 × 2 × 2 × 2 × 5

32 = 2 × 2 × 2 × 2 × 2

48 = 2 × 2 × 2 × 2 × 3

GCF of coefficients : (80,32,48) is 16.

2) GCF of variables :(b^4,b^2,b^4)

b^4= b × b × b × b

b^2 = b × b

b^4 =b × b × b × b

GCF of variables :(b^4,b^2,b^4) is b^2

3) GCF of c^3 and c: c is not the GCF of the polynomial. The variable c is not common to all terms, so a power of c should not have been factored out.

4) 80b^4-32b^2c^3+48b^4c

=16b^2(5b^2-2c^3+3b^2c)

David applied the distributive property.

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3 years ago
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