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soldier1979 [14.2K]
3 years ago
12

C. One Solution

Mathematics
1 answer:
Eva8 [605]3 years ago
7 0

Answer:

One Solution

Step-by-step explanation:

p+9=2p-3

subtract 9 from both sides

p+9=2p-3

-9 -9

simplify

p=2p-12

subtract 2p from both sides

p=2p-12

-2 -2

simplify

-p= -12

divide both sides by -1

p=1

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Which equation is the slope-intercept form of the line that passes through (6, –11) and is parallel to the graph of y = –2/3x +
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Answer:

<h2>The answer is option A</h2>

Step-by-step explanation:

Equation of a line is y = mx + c

where

m is the slope

c is the y intercept

To find the equation of the parallel line we must first find the slope of the original line

From the question the original line is

y = - ⅔x + 12

Comparing with the general equation above

Slope = -⅔

Since the lines are parallel their slope are also the same

Slope of parallel line = - ⅔

The equation of the line using point

(6, –11) and slope - ⅔ is

y + 11 =  -  \frac{2}{3} (x - 6) \\ y + 11 =  -  \frac{2}{3} x + 4 \\ y =  -  \frac{2}{3} x + 4  - 11

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3 0
3 years ago
When choosing an item from a group, researchers have shown that an important factor influencing choice is the item's location. T
natka813 [3]

Answer:

a) We have evidence of the " center stage effect" pair number 3 was selected 34 times almost double the probability of random process

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Step-by-step explanation:

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7 0
3 years ago
1) Anna and Jason have summer jobs stuffing envelopes for two different companies. Anna earns $20 for every 400 envelopes she fi
Margarita [4]

Answer:

The answer is below

Step-by-step explanation:

A) i)

For Anna initially, she has $0 from making 0 envelopes. Anna earns $20 for every 400 envelopes. Let x represent the number of envelopes and y the earnings. Hence this can be represented by the points (0, 0) and (400, 20). Using the equation of a line:

y-y_1=\frac{y_2-y_1}{x_2-x_1} (x-x_1)\\\\y-0=\frac{20-0}{400-0}(x-0)\\\\y=\frac{1}{20} x

The table is:

x:   200     400       600     800     1000

y:    10        20          30        40       50

ii)

Jason has $0 from making 0 envelopes. For every 250 envelopes he has $10. Let x represent the number of envelopes and y the earnings. Hence this can be represented by the points (0, 0) and (250, 10). Using the equation of a line:

y-0=\frac{10-0}{250-0}(x-0)\\\\y=\frac{1}{25} x

x:   200     400       600     800     1000

y:    8         16           24        32       40

The graph is plotted using geogebra online graphing

b) From the table of Anna and Jason we can see that Anna makes more stuffing than Jason for the same number of envelopes.

c) Anna has a savings of $100 initially. Hence this can be represented by the points (0, 100) and (250, 10). Using the equation of a line:

y-y_1=\frac{y_2-y_1}{x_2-x_1} (x-x_1)\\\\y-100=\frac{20-0}{400-100}(x-0)\\\\y=\frac{1}{15} x+100

Therefore from the graph there is a y intercept at 100. That is the earnings starts initially is $100.

The equation of a line is given as y = mx + b, where m is the slope and b is the y intercept (initial value of y at x = 0)

For the first graph, the slope is 1/20 with an initial value of 0 while for the second graph the slope is 1/15 with an initial value of 100

D) The trend line pass through the points (10, 10) and (100, 40), hence:

y-y_1=\frac{y_2-y_1}{x_2-x_1} (x-x_1)\\\\y-10=\frac{40-10}{100-10}(x-10)\\\\y-10=\frac{1}{3} (x-10)\\\\y=\frac{1}{3}x+\frac{20}{3}

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