Cos(A-B) = cosAcosB + sinAsinB
<span>
cos(</span>π/2 - θ) = cos(π/2)cosθ + sin(π/2)sinθ 
π/2 = 90°
cos(π/2) = cos90° = 0.        sin(π/2) = sin90° = 1
cos(π/2 - θ) = cos(π/2)cosθ + sin(π/2)sin<span>θ 
</span>
                   = 0*cosθ + 1*sin<span>θ  = </span>sin<span>θ
Therefore  </span>cos(π/2 - θ) = sin<span>θ
  
QED   </span> 
        
             
        
        
        
Answer:

General Formulas and Concepts:
<u>Pre-Alg</u>
- Order of Operations: BPEMDAS
<u>Algebra I</u>
- Slope Formula:  
Step-by-step explanation:
<u>Step 1: Define</u>
Point (40, 3000)
Point (60, 4000)
<u>Step 2: Find slope </u><em><u>m</u></em>
- Substitute:                     
- Subtract:                        
- Divide:                           
 
        
             
        
        
        
The answer is 9 cubic units