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QveST [7]
3 years ago
15

During February, Kevin will water has ivy every third day, and water his cactus every fifth day. On which date will Kevin first

water both plants together?
Mathematics
1 answer:
noname [10]3 years ago
5 0
Ok I’m bout to help you get this answer
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Given that 2x^2-5 = a(x+2)^2 _ b(x+1)+x for all values of X, find the value of a, of b and of c
SashulF [63]

It looks like you're asking to solve for the coefficients a,b,c such that

2x^2 - 5 = a(x+2)^2 - b(x+1) + c

Expanding the right side gives

2x^2 - 5 = ax^2 + 4ax + 4a - bx - b + c

2x^2 - 5 = ax^2 + (4a - b)x + (4a - b + c)

The coefficients on both sides must be equal, so

\begin{cases}a = 2 \\ 4a-b = 0 \\ 4a - b + c = -5\end{cases}

Solving the system yields \boxed{a=2 \implies b = 8 \implies c = -5}.

8 0
2 years ago
(4 x 5) ( 4 x 9)<br> i need help
Mashcka [7]

Answer:

(20) (36) this is your answer bro

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3 years ago
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A passing grade on the quiz was more than 8 points. Write an inequality that represents points needed for a passing grade.
Maksim231197 [3]

Answer:

p>8

Step-by-step explanation:

6 0
3 years ago
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4 4/5 divided by 3/10<br><br> Help
malfutka [58]

Answer:

16 is the answer

Step-by-step explanation:

4 4/5 x 10/3

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3 years ago
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Thompson and Thompson is a steel bolts manufacturing company. Their current steel bolts have a mean diameter of 131131 millimete
matrenka [14]

Correct question:

Thompson and Thompson is a steel bolts manufacturing company. Their current steel bolts have a mean diameter of 131 millimeters, and a standard deviation of 7 millimeters. If a random sample of 31" steel bolts is selected, what is the probability that the sample mean would differ from the population mean by more than 1.9 millimeters? Round your answer to four decimal places.

Answer:

0.1310

Step-by-step explanation:

Given:

Sample size, n = 31

mean, u = 131

standard deviation, \sigma = 7

X - u = 1.9

If a random sample of 31 steel bolts is selected, the probability that the sample mean would differ from the population mean by more than 1.9 millimeter, would be determined by:

Z = \frac{X-u}{\frac{\sigma}{\sqrt{n}}}

Z = \frac{1.9}{\frac{7}{\sqrt{31}}}

Z = 1.51

Probability =

P(|Z| > 1.51) =

P(Z < -1.51) + P(Z > 1.51)

= P(Z < -1.51) + 1 - P(Z > 1.51)

Using the standard normal table:

= NORMDIST(-1.51) = 0.0655;

NORMDIST(1.51) = 0.9345

Thus,

P = 0.0655 + 1 - 0.9345

= 0.1310

4 0
3 years ago
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