Describe the number line of the compound inequality

A researcher conducted an experiment to investigate the effects of working in crowded versus uncrowded conditions on the job sat

Artyom0805 [142]

In a research of investigating the effects of working in crowded versus uncrowded conditions on the job satisfaction of employees in a variety of work setting , working is a depending variable and crowding is an independent variable.

Given aim of the research is to investigate the effects of working in crowded conditions and uncrowded conditions.

We know that depending variable is a variable whose value is dependent on the other variable. Independent variable is a variable whose value does not dependent on the other variables.

In the given question working may be affected negatively in crowded environment means there will be less work in crowded environment and more work in uncrowded environment.

Hence the depending variable in research is working.

Learn more about depending variables at brainly.com/question/25223322

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4 0

2 years ago

Divide 72 in the ratio 7:2. show your work.

AVprozaik [17]

I think the answer is 3.5 cause when you divide it 7 go inside and 7 there's nothing you can multiply to get 7

5 0

4 years ago

A. 3.9 B. 1.0 C. 1.7 D 3.3

amm1812

Answer:

its for sure C

Step-by-step explanation:

4 0

3 years ago

A research study investigated differences between male and female students. Based on the study results, we can assume the popula

garri49 [273]

Using the normal distribution and the central limit theorem, it is found that the interval that contains 99.44% of the sample means for male students is (3.4, 3.6).

In a normal distribution with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

It measures how many standard deviations the measure is from the mean.

After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.

By the Central Limit Theorem, the sampling distribution of sample means of size n has standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

In this problem:

The mean is of $\mu = 3.5$ .

The standard deviation is of $\sigma = 0.5$ .

Sample of 100, hence $n = 100, s = \frac{0.5}{\sqrt{100}} = 0.05$

The interval that contains 95.44% of the sample means for male students is between Z = -2 and Z = 2, as the subtraction of their p-values is 0.9544, hence:

Z = -2:

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$