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erastovalidia [21]
3 years ago
8

38. The number of bottles a machine fills is proportional to the number of minutes the

Mathematics
1 answer:
kkurt [141]3 years ago
5 0

Answer:

250/20 = 12.5/min

2 min = 25 bottles

The machine fills 25 bottles every two minutes. So you should make points (minutes, bottles) at (0,0), (2,25), (4,50), (6,75), (8,100), (10,125) and draw a line connecting them.

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A runner is running a 10 km race. it takes her 17.5 minutes to reach the 2.5 km mark. at that rate, how long will it take her to
cluponka [151]
First find the unit rate. Do 17.5/2.5 and you get 7. Next just multiply that by 10 and voila. It takes her 70 minutes to run the whole race.
5 0
3 years ago
Can someone explain to me how to find the missing terms and common ratio of question #7, and how to answer #8 please
NeTakaya
7. general term of gp is given by ar^n-1
hence,4th term is given by

ar^3=15 ------(1)
ar^6=405-----(2)

equation 2/1,we get
r^3=27
so common ratio r=3
putting value of r in equation 1,
we get a=5/9

so gp upto 7 terms will be 5/9,5/3,5,15,45,135,405

8. a=3
given 4th term is -24
so ar^3=-24

substituting value of a we get r^3=-8
r^3= -2^3
so r = -2

using this x2 is ar= 3*-2=-6
           
               x3 is ar^2= 3*4=12

7 0
4 years ago
The set of measurements listed in order from greatest to least.
Ket [755]
Is there a picture that goes along with the question?
8 0
3 years ago
Read 2 more answers
Simplify the ratio go 35:14
dexar [7]

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5:2 is the lowest you could simplify it to

Step-by-step explanation:

8 0
3 years ago
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Cube A and cube B are similar solids. The volume of cube A is 27 cubic inches, and the volume of cube B is 125 cubic inches. How
katovenus [111]

The area of the base of cube B is 25/9 times larger than the area of the base of cube A.

<h3>How many times larger is the base area of cube B than the base area of cube A? </h3>

Because the cubes are similar, then we know that the dimensions of cube B are a dilation of scale factor K of the dimensions of cube A.

Then, the volume of cube B is K³ times the volume of cube A.

The area of any face of cube B is K² times the area of any face of cube A

From this we can write:

125 in³ = K³*27in³

(125/27) = K³

If we apply the cubic root in both sides, we get:

∛(125/27) = K = 5/3

Then the relation between the areas is equal to:

K² = (5/3)^2 = 25/9

The area of the base of cube B is 25/9 times larger than the area of the base of cube A.

If you want to learn more about dilations:

brainly.com/question/3457976

#SPJ1

5 0
2 years ago
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