Answer:
Denoting 2 desired numbers: x and y, then:
x + y = 17
2x = 3y + 4
<=>
x = 17 - y
2*(17 - y) = 3y + 4
<=>
x = 17 - y
34 - 2y = 3y + 4
<=>
x = 17 - y
5y = 30
<=>
y = 6
x = 17 - 6 = 11
Hope this helps!
:)
We know that this ratio is directly because the two magnitudes go up.
In this case we will get the <u>proportionality constant</u> by dividing any term of the second magnitude by the first.
<h3>For example: </h3>
![9 \: \div \: 3 \: = \: \boxed{3}](https://tex.z-dn.net/?f=9%20%5C%3A%20%20%5Cdiv%20%20%5C%3A%20%203%20%5C%3A%20%20%3D%20%20%5C%3A%20%20%5Cboxed%7B3%7D)
Now that we know that k = 3, we can know how much "<u>y</u>" will be if <em>x = 5</em>.
We just multiply:
![3 \: \times \: 5 \: = \: \boxed{ \bold{ 15}}](https://tex.z-dn.net/?f=3%20%5C%3A%20%20%5Ctimes%20%20%5C%3A%205%20%5C%3A%20%20%3D%20%20%5C%3A%20%5Cboxed%7B%20%5Cbold%7B%2015%7D%7D)
<h3>Answer: <u>y = 15</u></h3>
Answer:
2 hours
Step-by-step explanation:
The probability that a random sample of 12 second grade students results in a mean reading rate of more than 95 words per minute is 0.4582.
Given that the population mean,
= 90 wpm
The standard deviation of the population ,
= 10
Sample size, n = 12
Sample mean,
= 95
The reading rate of students follows the normal distribution.
Let z = ![\frac{\bar x - \mu}{\frac{\sigma}{\sqrt n} }](https://tex.z-dn.net/?f=%5Cfrac%7B%5Cbar%20x%20-%20%5Cmu%7D%7B%5Cfrac%7B%5Csigma%7D%7B%5Csqrt%20n%7D%20%7D)
= ![\frac{95 - 90}{\frac{10}{\sqrt 12} }](https://tex.z-dn.net/?f=%5Cfrac%7B95%20-%2090%7D%7B%5Cfrac%7B10%7D%7B%5Csqrt%2012%7D%20%7D)
= 1.732
Probability that the mean reading exceeds 95 wpm = P(
>95)
= P(z>1.732)
= 1- P(z<1.732)
= 0.4582
[The value 0.4582 found from the area under the normal curve using tables].
Learn more about Normal Distribution at brainly.com/question/27701525
#SPJ4
Answer:
Angle F, or 1; see below
Step-by-step explanation:
When two triangles are congruent, everything about them is equal. Angle C is congruent F because they are in the same position on the triangle.