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dalvyx [7]
3 years ago
7

How can you use a graph to check a factorization?

Mathematics
1 answer:
Ray Of Light [21]3 years ago
5 0
Find where the graph crosses the X axis
ex: graph crosses X axis at x=2 and x=6

factorization should be (x-2) and (x-6) for a quadratic
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Can someone help me with one question please And fast
m_a_m_a [10]

Answer:

equal to 4

Step-by-step explanation:

..................

5 0
3 years ago
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In a geometric sequence a5=36 and a7=16. use the geometric meant to find the value of a6
hammer [34]
Simple this is a geometric sequence answer is 32 becauase geometric sequences in this term mean a5*2, giving us 32.
5 0
3 years ago
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Prove the following by induction. In each case, n is apositive integer.<br> 2^n ≤ 2^n+1 - 2^n-1 -1.
frutty [35]
<h2>Answer with explanation:</h2>

We are asked to prove by the method of mathematical induction that:

2^n\leq 2^{n+1}-2^{n-1}-1

where n is a positive integer.

  • Let us take n=1

then we have:

2^1\leq 2^{1+1}-2^{1-1}-1\\\\i.e.\\\\2\leq 2^2-2^{0}-1\\\\i.e.\\2\leq 4-1-1\\\\i.e.\\\\2\leq 4-2\\\\i.e.\\\\2\leq 2

Hence, the result is true for n=1.

  • Let us assume that the result is true for n=k

i.e.

2^k\leq 2^{k+1}-2^{k-1}-1

  • Now, we have to prove the result for n=k+1

i.e.

<u>To prove:</u>  2^{k+1}\leq 2^{(k+1)+1}-2^{(k+1)-1}-1

Let us take n=k+1

Hence, we have:

2^{k+1}=2^k\cdot 2\\\\i.e.\\\\2^{k+1}\leq 2\cdot (2^{k+1}-2^{k-1}-1)

( Since, the result was true for n=k )

Hence, we have:

2^{k+1}\leq 2^{k+1}\cdot 2-2^{k-1}\cdot 2-2\cdot 1\\\\i.e.\\\\2^{k+1}\leq 2^{(k+1)+1}-2^{k-1+1}-2\\\\i.e.\\\\2^{k+1}\leq 2^{(k+1)+1}-2^{(k+1)-1}-2

Also, we know that:

-2

(

Since, for n=k+1 being a positive integer we have:

2^{(k+1)+1}-2^{(k+1)-1}>0  )

Hence, we have finally,

2^{k+1}\leq 2^{(k+1)+1}-2^{(k+1)-1}-1

Hence, the result holds true for n=k+1

Hence, we may infer that the result is true for all n belonging to positive integer.

i.e.

2^n\leq 2^{n+1}-2^{n-1}-1  where n is a positive integer.

6 0
3 years ago
I need help with this
rodikova [14]
You need to expand (4x-7)(x+3), multiplying each term in the first bracket by each term in the second bracket, in order to get 4x^2+5x-21. Hope that helps!
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Which expression is equivalent to 3.3.3.3
nikdorinn [45]

Answer:

I'm not sure but i think it's 34y

Step-by-step explanation:

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