Recall the Maclaurin expansion for cos(x), valid for all real x :
Then replacing x with √5 x (I'm assuming you mean √5 times x, and not √(5x)) gives
The first 3 terms of the series are
and the general n-th term is as shown in the series.
In case you did mean cos(√(5x)), we would instead end up with
which amounts to replacing the x with √x in the expansion of cos(√5 x) :
Answer:
39.407m
Step-by-step explanation:
sin 66deg = 36/length of cable
length of cable = 36/sin 66deg = 39.407m (5sf)
<span>You only need an estimate? Great. Think of the necessary material as 6 yards, so ten costumes would take 60 yards. Then think of the fabric on hand as 240 yards, so taking 60 yards away from that would leave [an estimated] 180 yards of fabric.
For an equation, use:
F" = F' - 5.8 C
Where F' is the initial fabric stock, F" is the remaining fabric, and C is the count of costumes.
In exact numbers, the formula works out to:
F" = 238.2 - (5.8 * 10)
F" = 180.2
The estimate was very close.
Good luck.</span>
Answer:
A:29
Step-by-step explanation:
1/4 = 0.25
8.25 + 0.25w = 10.25
0.25w = 10.25 - 8.25
0.25w = 2
w = 2 / 0.25
w = 8 <===
