6)
KM bisects on <NKL so m<MKN = m<MKL = 3x + 5
2(m<MKL) + m<JKN = 180
2(3x+5) + 8x + 2 = 180
6x + 10 + 8x + 2 = 180
14x + 12 = 180
14x = 168
x = 12
so
m<MKN = m<MKL = 3x + 5 = 3(12) + 5 = 36 + 5 = 41
answer
b. 41
7)
2 supplementary has sum = 180
x + x + 14 = 180
2x + 14 = 180
2x = 166
x = 83
x + 14 = 83 + 14 = 97
2 angles are 83 and 97
answer
b. 83, 97
The answer is a. $35. First you multiply 25 by .40. Then you add the product to 25.
Y-2x=8
16+4x=2y
Rearrange the first equation equal to y
Y=2x+8
Sub the rearranged equation into the second equation and solve for x
16+4x=2(2x+8)
16+4x=4x+16
16-16=4x-4x
0=0
There would be no solution
Hope this helps!
