23−11 Enter your answer as a fraction in simplest form by filling in the boxes. 30 30

Mathematics

1 answer:

mamaluj [8]3 years ago

6 0

23 - 11 = 12

12 = 12/1

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Find the absolute maximum and absolute minimum values of f on the given interval. f(x) = 6x3 ? 9x2 ? 108x + 2, [?3, 4]

SVEN [57.7K]

Assuming the question marks are minus signs
to find max, take derivitive and test 0's and endpoints

take derivitive
f'(x)=18x²-18x-108
it equal 0 at x=-2 and 3
if we make a sign chart to find the change of signs
the sign changes from (+) to (-) at x=-2 and from (-) to (+) at x=3
so a reletive max at x=-2 and a reletive min at x=3

test entpoints

f(-3)=83
f(-2)=134
f(3)=-241
f(4)=-190

the min is at x=3 and max is at x=-2

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4 years ago

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3 years ago

What is the answer for this Problem?

geniusboy [140]

Answer:

Increasing on the interval(s) $-2\leq x\leq -4$

Decreasing on the interval(s) $-1\leq y\leq 1$

Step-by-step explanation:

Anytime the graph is going upward, the function is increasing. However, anytime the graph goes down, the function is decreasing. Look at the image below for further reference. Also, when the function is increasing, the slope is positive, and when the function is decreasing the slope is negative.

The increasing interval of the graph is -3

The decreasing interval of the graph is 0.5

Since the values are in the middle of the interval, it automatically becomes the answer.