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2 years ago

Multiply to get 3, add to get 8

Mathematics

1 answer:

Phantasy [73]2 years ago

8 0

If you are doing a quadratic, you wil have to do quadratic formula, if you are just doing that, no solution.

You might be interested in

What is the diameter of a cone with height 8 m and volume 150 m3 ? (1 point 7.5 m 15 m?

Hitman42 [59]

This is the concept of volume of solid materials, we are required to find the diameter of cone with height 8 and volume 150 m^3.
volume of cone is given by;V=1/3 (pi*r^2*h)
making r^2 the subject we get;
V/(pi*h)=r^2
inserting the values in our formula we get:
150/(pi*8)=r^2
r^2=5.97
thus;
r=sqrt(5.97)=2.44
But ;
diameter=2*radius
thus
diameter=2.44*2
=4.88 m

3 0

3 years ago

It is known that 50% of adult workers have a high school diploma. If a random sample of 8 adult workers is selected, what is the

son4ous [18]

Answer:

85.56% probability that less than 6 of them have a high school diploma

Step-by-step explanation:

For each adult, there are only two possible outcomes. Either they have a high school diploma, or they do not. The probability of an adult having a high school diploma is independent of other adults. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

50% of adult workers have a high school diploma.

This means that $p = 0.5$

If a random sample of 8 adult workers is selected, what is the probability that less than 6 of them have a high school diploma

This is P(X < 6) when n = 8.

$P(X < 6) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{8,0}.(0.5)^{0}.(0.5)^{8} = 0.0039$

$P(X = 1) = C_{8,1}.(0.5)^{1}.(0.5)^{7} = 0.0313$

$P(X = 2) = C_{8,2}.(0.5)^{2}.(0.5)^{6} = 0.1094$

$P(X = 3) = C_{8,3}.(0.5)^{3}.(0.5)^{5} = 0.2188$

$P(X = 4) = C_{8,4}.(0.5)^{4}.(0.5)^{4} = 0.2734$

$P(X = 5) = C_{8,5}.(0.5)^{5}.(0.5)^{3} = 0.2188$

$P(X < 6) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) = 0.0039 + 0.0313 + 0.1094 + 0.2188 + 0.2734 + 0.2188 = 0.8556$

85.56% probability that less than 6 of them have a high school diploma

7 0

3 years ago

1046.4 carried out to two decimal places

julia-pushkina [17]

Answer:

1046

Step-by-step explanation:

7 0

3 years ago

Find the derivative with respect to x of y = (3x + x^2)^5

RSB [31]

<h2>The required "option A) $5(3x + x^2)^{4} (3+2x)$ " is correct.</h2>

Step-by-step explanation:

We have,

$y = (3x + x^2)^5$ ..... (1)

To find, $\dfrac{dy}{dx}$ = ?

Differentiating equation (1) w.r.t. 'x', we get

$\dfrac{dy}{dx}= \dfrac{d[(3x + x^2)^5]}{dx}$

⇒ $\dfrac{dy}{dx}=5(3x + x^2)^{5-1} \dfrac{d(3x + x^2)}{dx}$

[ ∵ $y=x^{n}$ ⇒ $\dfrac{dy}{dx}=nx^{n-1}$ ]

⇒ $\dfrac{dy}{dx}=5(3x + x^2)^{4} (3(1) + 2x^{2-1})$

⇒ $\dfrac{dy}{dx}=5(3x + x^2)^{4} (3+2x)$

Thus, the required "option A) $5(3x + x^2)^{4} (3+2x)$ " is correct.

3 0

3 years ago

A graphing calculator is recommended.

kogti [31]

Answer:

$Q(3\,min) = 0.349\,pd$

Step-by-step explanation:

The expression for the salt in the barrel is:

$Q(t) = 6\cdot (1-e^{-0.02\cdot t})$

The quantity of salt in the barrel after 3 minutes is:

$Q(3\,min) = 6\cdot [1-e^{-0.02\cdot (3\,min)}]$

$Q(3\,min) = 0.349\,pd$

5 0

3 years ago