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ExtremeBDS [4]
3 years ago
10

Using square ABCD, calculate the measure of ZEDC, if mZECD = 45°. =

Mathematics
2 answers:
never [62]3 years ago
8 0

Answer:

45

Step-by-step explanation:

In square, the diagonals bisect each other at 90,

∠DEC = 90°

ED = EC

So, ΔECD is isosceles triangle.

Angles opposite to equal sides are equal.

∠EDC = ∠ECD = 45

pantera1 [17]3 years ago
7 0

Answer:

45°

Step-by-step explanation:

Two diagonals of a square intersect at right angle, I.e., 90°

BD and AC are two such diagonals of the square ABCD.

Since, they intersect at 90°:

∠DEC = 90°

We're given the value of ∠ECD and that is 45°

- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -

<h3><u>Observing</u><u> </u><u>Triangle EDC:</u></h3>

<em>Sum of all angles in a triangle = 180°</em>

=> ∠DEC + ∠ECD + ∠EDC = 180°

=> 90 + 45 + ∠EDC = 180°

=> 135 + ∠EDC = 180

=> ∠EDC = 180 - 135

<u>=> ∠EDC = 45</u>

- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -

<h3><u>Answer</u><u>:</u></h3>

Hence, we know the value of ∠EDC and that is 45°

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8 0
3 years ago
The table below models the cost, y, of using a high-efficiency washing machine and a standard washing machine over x number of y
SSSSS [86.1K]

ANSWER:

i) y = 25x + 500

ii) y = 30x + 400

iii) The washing machines would cost the same amount after 20 years of use

iv) Standard machine

Step-by-step explanation:

i)

We are to determine a straight line equation that models the cost of High-Efficiency washing machine over the years;

The first step step is to determine the slope of the line,

( change in y) / ( change in x ) = (550 - 525) / ( 2 - 1) = 25

The equation is slope-intercept form will be;

y = 25x + c

Where y is the cost of the High-Efficiency washing machine and x the number of years. To determine the y-intercept, c, we use any pair of points given in the data table;

when x = 1, y = 525

525 = 25(1) + c

c = 500

Therefore;

y = 25x + 500

ii)

The straight line equation that models the cost of Standard washing machine over the years;

Slope = (460 - 430) / (2 - 1) = 30

The equation is slope-intercept form will be;

y = 30x + c

when x = 1, y = 430

430 = 30(1) + c

c = 400

Therefore;

y = 30x + 400

Where y is the cost of the standard washing machine and x the number of years.

iii)

Given the cost functions for both machines over the number of years, we simply equate the two equations and determine the value of x when both machines would cost the same amount;

We have the cost functions;

y = 25x + 500

y = 30x + 400

Equating the two and solving for x;

25x + 500 = 30x + 400

500 - 400 = 30x - 25x

100 = 5x

x = 20

Therefore, the washing machines would cost the same amount after 20 years of use.

iv)

In order to determine which machine would be the more practical purchase if kept for 9 years we use the cost functions obtained in i) and ii)

The cost function of the High-Efficiency washing machine is;

y = 25x + 500

To determine the cost, we solve for y given x = 9

y = 25(9) + 500

y = 725

The cost function of the Standard washing machine is;

y = 30x + 400

We solve for y given x = 9

y = 30(9) + 400

y = 670

Comparing the two values obtained, the cost for the Standard washing machine is more practical.

3 0
2 years ago
Read 2 more answers
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quester [9]

9514 1404 393

Answer:

  • 150.72 cm³
  • 314 cm³
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Step-by-step explanation:

Put the given numbers in the relevant formula and do the arithmetic.

<u>right cylinder</u>

   V = πr²h = 3.14(4 cm)²(3 cm) = 3.14×48 cm³ = 150.72 cm³

<u>cone</u>

  V = 1/3πr²h = 1/3(3.14)(5 cm)²(12 cm) = 3.14×100 cm³ = 314 cm³

<u>pyramid of unknown shape</u>

  V = 1/3Bh = 1/3(16 cm²)(30 cm) = 160 cm³

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  V = 1/3s²h = 1/3(3 cm)²(16 cm) = 48 cm³

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2 years ago
A bag contains 30 lottery balls numbered 1-30 a ball is selected replaced then another is drawn find each probability
iogann1982 [59]
#1) 5/20
#2) 7/300
#3) 3/50
#4) 5/20

Explanation
For #1:
There are 15 even numbers out of 30.  Since it is replaced before drawing the second ball, there will be 15 odd numbers out of 30.  This gives us
15/30(15/30) = 225/900 = 5/20.

For #2:
There is 1 7 out of 30; then there are 14 numbers greater than 16 out of 30:
1/30(14/30) = 14/900 = 7/300

For #3:
There are 6 multiples of 5 out of 30; then there are 9 prime numbers out of 30:
6/30(9/30) = 54/900 = 3/50

For #4:
There are 15 even numbers out of 30; then there are still 15 even numbers out of 30:
15/30(15/30) = 225/900 = 5/20
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