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ExtremeBDS [4]
3 years ago
10

Using square ABCD, calculate the measure of ZEDC, if mZECD = 45°. =

Mathematics
2 answers:
never [62]3 years ago
8 0

Answer:

45

Step-by-step explanation:

In square, the diagonals bisect each other at 90,

∠DEC = 90°

ED = EC

So, ΔECD is isosceles triangle.

Angles opposite to equal sides are equal.

∠EDC = ∠ECD = 45

pantera1 [17]3 years ago
7 0

Answer:

45°

Step-by-step explanation:

Two diagonals of a square intersect at right angle, I.e., 90°

BD and AC are two such diagonals of the square ABCD.

Since, they intersect at 90°:

∠DEC = 90°

We're given the value of ∠ECD and that is 45°

- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -

<h3><u>Observing</u><u> </u><u>Triangle EDC:</u></h3>

<em>Sum of all angles in a triangle = 180°</em>

=> ∠DEC + ∠ECD + ∠EDC = 180°

=> 90 + 45 + ∠EDC = 180°

=> 135 + ∠EDC = 180

=> ∠EDC = 180 - 135

<u>=> ∠EDC = 45</u>

- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -

<h3><u>Answer</u><u>:</u></h3>

Hence, we know the value of ∠EDC and that is 45°

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What is the distance between the lines y = 2x and y = 2x+5? Round your answer to the nearest tenth.
Ilia_Sergeevich [38]

The distance between both lines is 2.24 units

Step-by-step explanation:

There is no straight method to find the distance between two lines. The distance can be found out by finding a point on one line and then finding the distance of that point from the other line. The y-coordinate of point is obtained by putting any value of x in equation . The x and y combined give us the point.

Given

y=2x\\Putting\ x=1\\y=2(1)\\y=2\\So, the\ point\ on\ y=2x\ is\ (1,2)

We have to find the distance of this point from y=2x+5

y=2x+5\\Subtracting\ y\ from\ both\ sides\\y-y=2x+5-y\\2x-y+5=0

The formula for finding distance of a point (x,y) from a line is:

d=\frac{|Ax+By+C|}{\sqrt{A^2+B^2}}

A=2

B=-1

C=5

Putting the values in the formula

d=\frac{|(2)(1)+(-1)(2)+5|}{\sqrt{(2)^2+(-1)^2}}\\d=\frac{|2-2+5|}{\sqrt{4+1}}\\d=\frac{|5|}{\sqrt{5}}\\d=\frac{5}{\sqrt{5}}\\d=2.236\ units

Rounding off will give: 2.24 units

The distance between both lines is 2.24 units

Keywords: Equations of lines

Learn more about distance in lines at:

  • brainly.com/question/7449065
  • brainly.com/question/7490805

#LearnwithBrainly

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3 years ago
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