You need to add the sum in order to find the answer
Answer:
4.605170185988091
Step-by-step explanation:
ln 100 = 4.605170185988091
e^4.605170185988091 = 100
Let me see the whole thing, theres no enough info
Answer:
Check the explanation
Step-by-step explanation:
in this particular type of problems,we have to go with the cases.we know there would be a 50 odd-even pairs between 1 and 100.
1st case: 1 is placed at the head position of given set S.so there is a chance of only one even number beside 1.so there are 50×98!
2nd case: 1 is placed at tail position of S.so there is again a chance of one even number beside 1. so there are
50×98!
3rd case: 1 is placed neither at head nor at tail.1 can be at rest 98 places.lets fix the place of 1.then the choices are difference between permuting all the numbers and 1 surrounded by two odd numbers.
i.e., 99! - 49p2 ×97!
so total choces are = 2×50×98! + 99! - 49p2 × 97!
= 7448 × 97! + 99!
(x+1)*(x+8) = x^2 + 9x + 8