The center of the circle is expressed as (h,k) in the standard form of equation. In this case, the diameter endpoints are <span>(-3, 8) and (7, 4). Hence the circle center has coordinates which are the midpoints of the two points.
x = (-3 + 7) /2 = 2
y = (8 + 4) /2 = 6
hence the center of the circle is (2,6)</span>
Answer: x² + y² - 2x - 8y + 13 = 0
Step-by-step explanation:
the equation of the circle is in the form (x - a)² + (y - b)² = r²
where (a,b) is the center of the circle and r is the radius
hence the equation is
(x - 1)² + (y - 4)² = 2²
x²-2x+1+y²-8y+16= 4
x²+ y² -2x- 8y + 17 =4
x² + y² - 2x - 8y = -13
x² + y² - 2x - 8y + 13 = 0
Answer:
$2.08
Step-by-step explanation:
2 7/8= 23/8 divided 1.38
Answer:
(7,3)
Step-by-step explanation:
you can add the equations together to eliminate y and first solve for x
(x-3y = -2) + (x+3y=16) = (2x = 14)
x = 7
then plug x into one of the equations to solve for y
(7) - 3y = -2
9 = 3y
y = 3
the solution is (7,3)
