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Alexxandr [17]
3 years ago
12

A new car is purchased for 20300 dollars. The value of the car depreciates at 8.75% per year. What will the value of the car be,

to the nearest cent, after 12 years?
Mathematics
1 answer:
mina [271]3 years ago
7 0

Answer:

<u>The value of the car, to the nearest cent, after 12 years will be $ 6,765.35</u>

Step-by-step explanation:

Let's recall that depreciation on a car can be determined by the formula:

V = C * (1 - r)^t , where:

V is the value of the car after t years,

C is the original cost

r is the rate of depreciation

t is the number of years of utilization of the car

Therefore, we have:

V = C * (1-r)^t

V = 20,300 * (1 - 0.0875)¹²

V = 20,300 * 0.333268

<u>V = 6,765.35 (rounding to the nearest cent)</u>

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Answer:

0.6472 = 64.72% probability that a randomly selected page does not need to be retyped.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

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This means that \mu = 3

What is the probability that a randomly selected page does not need to be retyped?

Probability of at most 3 errors, so:

P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)

In which

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 0) = \frac{e^{-3}*3^{0}}{(0)!} = 0.0498

P(X = 1) = \frac{e^{-3}*3^{1}}{(1)!} = 0.1494

P(X = 2) = \frac{e^{-3}*3^{2}}{(2)!} = 0.2240

P(X = 3) = \frac{e^{-3}*3^{3}}{(3)!} = 0.2240

Then

P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0.0498 + 0.1494 + 0.2240 + 0.2240 = 0.6472

0.6472 = 64.72% probability that a randomly selected page does not need to be retyped.

3 0
2 years ago
PLEASE HELP WITHIN 5 MINUTES! Be as accurate as possible!
Nookie1986 [14]

Answer:

2,75in

4,25in

33in²

Step-by-step explanation:

shorter base is 2,75in

larger base is 4,25in

S=11+10,5+9+2,5=33in²

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A pollster obtains a list of all the residential addresses in a certain town, and uses a computer random number generator to cho
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Answer:

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2 years ago
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Answer:

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From the question we are told that

   The mean is  \= x  =  60

    The standard deviation is  \sigma  =  21

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Generally the standard deviation of the sample mean is mathematically represented as  

               \sigma _ {\=  x } =  \frac{\sigma  }{\sqrt{n} }

substituting values

               \sigma _ {\=  x } =  \frac{ 21 }{\sqrt{60} }

               \sigma _ {\=  x } = 2.711

4 0
2 years ago
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