Answer:
B] f(n) = 6(3)n − 1; f(5) = 486
Step-by-step explanation:
First, you have to identify which type of relation the points have. From the graph you can tell that it's an exponential growth. The x values change in the same amount every time, in this case by 1.
So if the relation is exponential, if we divide the y coordinates you should get the same result every time.
18 / 6 = 3
54 / 18 = 3
162 / 54 = 3
So the y value increases 3 times. That means that the next value should be 162*3 = 486.
Answer:
Company B.
Step-by-step explanation:
On the graph, when x is 1, y is 50. That means it is $50 for one window. On the chart, when there is 1 window, the cost is $55. So, company B is more expensive!
Answer:
Part A is $21 and part B is $30.21
-1, 0.5, 2/3, 1.1 is the order of the numbers from least to greatest
Answer:
The system of equations that models the problem is:

Step-by-step explanation:
A system of equations is a set of two or more equations with several unknowns in which we want to find a common solution. So, a system of linear equations is a set of (linear) equations that have more than one unknown that appear in several of the equations. The equations relate these variables or unknowns to each other.
In this case, the unknown variables are:
- H: price of a can of corn beef hash
- C: price of a can of creamed chipped beef
Knowing the unit price of a product, the price of a certain quantity of that product is calculated by multiplying that quantity by the unit price. So the price for 2 cans of ground beef hash can be calculated as 2 * H and the price for 3 cans of ground beef with cream can be calculated as 3 * C. Jan paid $ 4.95 for those amounts from both cans. This means that the sum of the can prices must be $ 4.95. So: <u><em>2*H + 3*C= 4.95 Equation (A)</em></u>
Thinking similarly, if Wayne bought 3 cans of corn beef hash and 2 cans of creamed chipped beef for $5.45, Wayne's buy can be expressed by the equation:
<u><em>3*H + 2*C= 5.45 Equation (B)</em></u>
Finally, <u><em>the system of equations that models the problem is:</em></u>
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