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3 years ago

Would shadows be 3 dimensional in 4 dimenional space

1 answer:

azamat3 years ago

4 0

4 Dimensional shapes can cast 3 dimensional shadows. ... Maybe a shadow is the fourth dimension, its been here all the time.

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Hi I need help with the question in the image. Step by step, thank you!

VashaNatasha [74]

The exponential function is $f(x) = 18(12)^{-x-4} + 2$

<h3>How to determine the equation?</h3>

An exponential function is represented as:

y = b^x

Where b represents the base.

The base is given as:

b = 12

So, we have:

y = (12)^x

It is vertically compressed by a factor of 1/8.

So, we have:

y = 18(12)^x

When reflected across the y-axis, we have:

$y = 18(12)^{-x}$

The horizontal asymptote is y = 2.

So, we have:

$y = 18(12)^{-x} + 2$

It passes through the point (-3, 4).

So, we shift the function to the right by 4 units

$y = 18(12)^{-x-4} + 2$

Express as a function

$f(x) = 18(12)^{-x-4} + 2$

Hence, the exponential function is $f(x) = 18(12)^{-x-4} + 2$

Read more about exponential functions at:

brainly.com/question/14355665

#SPJ1

6 0

1 year ago

PLEASE HELP ASAP

Crank

Option D: $f(x)=-2(x+2)(x-4)$ is the function

Explanation:

Let the general form of quadratic equation be $y=a x^{2}+b x+c$

The function passes through the intercepts $(-2,0)$ and $(4,0)$ and also passes though the point $(-1,10)$

Substituting the points $(-2,0)$ , $(4,0)$ and $(-1,10)$ in the equation $y=a x^{2}+b x+c$ , we get,

$4a -2b+c=0$ -----------(1)

$16a +4b+c=0$ ----------(2)

$a-b+c=10$ -----------(3)

Subtracting (1) and (2), we get,

$\ \ 4a -2b+c=0\\ 16a +4b+c=0\\\---------\\ \ \ -12a-6b=0$ -----------(4)

Subtracting (2) and (3), we get,

$16a +4b+c=0\\\ \ a \ \ - \ \ b \ +c=10\\---------\\15a+5b=-10$ ------------(5)

Multiplying equation (4) by 5 and equation (5) by 4, to cancel the term b when adding, we get,

$-60a-30b=0\\\ 90a+30b=-60\\--------\\30a=-60\\\ \ a=-2$

Thus, the value of a is $a=-2$

Substituting $a=-2$ in equation (4), we get,

$\begin{aligned}-12 a+6 b &=0 \\-12(-2)-6 b &=0 \\ 24-6 b &=0 \\ 24 &=6 b \\ 4 &=b \end{aligned}$

Thus, the value of b is $b=4$

Now, substituting the value of a and b in equation (1), we have,

$\begin{aligned} 4 a-2 b+c &=0 \\ 4(-2)-2(4)+c &=0 \\-8-8+c &=0 \\ c &=16 \end{aligned}$

Thus, the value of c is $c=16$

Now, substituting the value of a,b and c in the general formula $y=a x^{2}+b x+c$ , we get,

$y=-2x^{2} +4x+16$

Taking out the common term as -2 we get,

$y=-2(x^{2} -2x-8)$

Factoring , we get,

$y=-2(x+2)(x-4)$

Thus, the function is $f(x)=-2(x+2)(x-4)$

7 0

2 years ago

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Fynjy0 [20]

Answer:

Step-by-step explanation:

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2 years ago

Find the unit rate. A 6oz jar of jalapeños cost $2.34

Kazeer [188]

Answer:

1oz cost $0.39 which will be the unite rate

Step-by-step explanation:

6 0

3 years ago

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Mark each of the following as true or false and explain how you know.

earnstyle [38]

True
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(I think)

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3 years ago

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