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2 years ago

7

The hypotenuse of a right triangle is 6 feet long. One leg is 2 feet longer than the other. Find the length of each leg to the n

earest hundredth of a foot.

1 answer:

Gemiola [76]2 years ago

8 0

Here is a diagram explaining the information

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X sqaured plus 4x plus 20 equlas 12x minus 5

skelet666 [1.2K]

Answer:

x² + 4x + 20 = 12x - 5

x² + 4x - 12x + 20 + 5 = 0

x² - 8x + 25 = 0

Δ = √b² - 4ac

= √(-8)² - 4×1×25

= √64-100

= √(-36)

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3 years ago

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3 years ago

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3 years ago

Which is greater .836 or .83

anygoal [31]

Just do like this
.836
.83
.83=.830
which one has bigger numbers?
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the answer is .836

4 0

3 years ago

If cos Θ = square root 2 over 2 and 3 pi over 2 < Θ < 2π, what are the values of sin Θ and tan Θ?

KIM [24]

Answer:

The answer is

$sin(\theta)=-\frac{\sqrt{2}}{2}$

$tan(\theta)=-1$

Step-by-step explanation:

we know that

$tan(\theta)=\frac{sin(\theta)}{cos(\theta)}$

$sin^{2}(\theta)+cos^{2}(\theta)=1$

In this problem we have

$cos(\theta)=\frac{\sqrt{2}}{2}$

$\frac{3\pi}{2}$

so

The angle $\theta$ belong to the third or fourth quadrant

The value of $sin(\theta)$ is negative

Step 1

Find the value of $sin(\theta)$

Remember

$sin^{2}(\theta)+cos^{2}(\theta)=1$

we have

$cos(\theta)=\frac{\sqrt{2}}{2}$

substitute

$sin^{2}(\theta)+(\frac{\sqrt{2}}{2})^{2}=1$

$sin^{2}(\theta)=1-\frac{1}{2}$

$sin^{2}(\theta)=\frac{1}{2}$

$sin(\theta)=-\frac{\sqrt{2}}{2}$ ------> remember that the value is negative

Step 2

Find the value of $tan(\theta)$

$tan(\theta)=\frac{sin(\theta)}{cos(\theta)}$

we have

$sin(\theta)=-\frac{\sqrt{2}}{2}$

$cos(\theta)=\frac{\sqrt{2}}{2}$

substitute

$tan(\theta)=\frac{-\frac{\sqrt{2}}{2}}{\frac{\sqrt{2}}{2}}$

$tan(\theta)=-1$

8 0

3 years ago

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