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NARA [144]
2 years ago
10

(3x – 1) : (x - 2) = x – 2x (x—4) срочно, сор.

Mathematics
1 answer:
RSB [31]2 years ago
6 0

\frac{3x-1}{x-2}=x-2x(x-4)  \frac{3x-1}{x-2}=x-2x^{2} +8x \\\frac{3x-1}{x-2}=-2x^{2} +9x3x-1= (-2x^{2} +9x)(x-2)\\3x-1= -2x^3+4x^{2} +9x^{2} -18x\\3x-1=-2x^3+13x^{2} -18x\\2x^3 -13x^{2} +18x+3x -1=0\\2x^3 -13x^{2}+21x-1=0\\ x =0.05 /or/x=3.7

ok done. Thank to me :>

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Translate and solve: Three more than the difference of 6s and 5s is equal to the difference of 1/12 and 1/6
PilotLPTM [1.2K]

Answer:

a. (6s-5s)+3=\frac{1}{12}-\frac{1}{6}

b. s=-\frac{37}{12}

Step-by-step explanation:

You need to remember that:

1. The word "more" indicates Addition.

2. The "Difference" is the result of a Subtraction.

a. Then, knowing this information, you know that:

- "The difference of 6s and 5s" must be expressed as:

6s-5s

- Then, "Three more than the difference of 6s and 5s " is:

(6s-5s)+3

- "The difference of  \frac{1}{12} and \frac{1}{6} " can be expressed in this form:

\frac{1}{12}-\frac{1}{6}

Therefore, "Three more than the difference of 6s and 5s is equal to the difference of  \frac{1}{12} and \frac{1}{6} " is:

(6s-5s)+3=\frac{1}{12}-\frac{1}{6}

b. Solve for "s" in order to find its value:

s+3=-\frac{1}{12}\\\\12(s+3)=-1\\\\12s+36=-1\\\\12s=-1-36\\\\s=-\frac{37}{12}

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Read 2 more answers
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