The answer is "C", "MW".
In the given problem, the place QMW and plane RMW. These planes intersect at MW, in which intersection is either a point, line or curve that an entity or entities both possess or is in contact with but if we see in Euclidean<span> geometry, the intersection of two planes is called a “line”. </span>In the plane we can understand that the common line for both plane QMW and plane RMW is MW.
Answer:
P____Q____R
PR= PQ+ QR
(14x-13) = (5x-2)+(6x+1)
14x-13= 11x – 1
14x – 11x = 13–1
3x = 12
x= 12/ 3
x= 4
PR= 14x – 13 = 14 (4) – 13 = 18 – 13= 5
If you want (PQ , QR ) this is the solution
PQ =5x-2=5(4)-2=20-2=18
QR =6x+1=6(4)+1=24+1=25
I hope I helped you^_^
Joanna would have spent $8.94 on apples at the farmers market.
Answer:
<h2>y = 3x - 3</h2>
Step-by-step explanation:
The slope-intercept form of an equation of a line:
<em>m</em><em> - slope</em>
<em>b</em><em> - y-intercept</em>
<em />
We have the slope <em>m = 3</em>, and the point <em>(2, 3)</em>.
Put the value of slope and the coordinates of the given pint (x = 2, y = 3) to the equation of a line:
<em>subtract 3 from both sides</em>
Finally:
