Two ratioa that are equivalent to 9/12 are
3/4
18/24
-3b+ac=4
Move c to the left and - 3b to the right
ac-c=-4+3b
Now factor by c at the left
c(a-1)=-4+3b
Divide the right by a-1
C=(-4+3b)/(a-1)
Answer:
The shadow is 11 Ft. away from the pole base.
Step-by-step explanation:
I just usually do this trick in situations like these where if <em>x</em> equals 1, and <em>y</em> equals 2, then <em>z </em>is gonna be 3. 2 goes after 1, and 3 goes after 2. This trick can work in other counting-up situations like this, as long as the number go up, and are right next to each other.
we are given
62% of the students take math
so,
49% take science
38% take both science and math
n(M∩S)=38
now, we can use union formula
n(M∪S)=n(M)+n(S) -n(M∩S)
now, we can plug values
and we get
n(M∪S)=62+49 -38
n(M∪S)=73
so,
the percentage takes at least one science or math course is 73%..........Answer
Answer:
f(x) = 54(two-thirds) Superscript x minus 1
Step-by-step explanation:
Given that:
First peak : 36 / 54=2/3
Second peak : 24 / 36 = 2/3
The common ratio here is 2/3 ; which mean each bounce height is 2/3 of previous height
Modeling this using geometric progression :
An=a1r^(n-1)
An = nth term of a geometric progression
a1=first term
r=common ratio = 2/3
n = nth term
a1=54
Substituting into the above formular :
An=54(2/3)^(n-1)
