3 years ago

What is the equation of y=2x-6 in standard form?

Mathematics

2 answers:

GalinKa [24]3 years ago

8 0

Answer:

y-2x+6=0

Step-by-step explanation:

prisoha [69]3 years ago

3 0

Answer:

2x - y = 6

Step-by-step explanation:

The equation of a line in standard form is

Ax + By = C ( A is a positive integer and B, C are integers )

Given

y = 2x - 6 ( add 6 to both sides )

y + 6 = 2x ( subtract y from both sides )

6 = 2x - y, that is

2x - y = 6 ← in standard form

You might be interested in

Which of the following are polynomials?

Pavel [41]

B and D are the correct choices

4 0

3 years ago

Read 2 more answers

Identify the domain of the function shown in the graph.

BARSIC [14]

$x \geqslant 0$
D

5 0

3 years ago

Read 2 more answers

Which expression and could you explain

docker41 [41]

I would say d. Hope that helps

4 0

4 years ago

Read 2 more answers

A number, y, is equal to twice the sum of a smaller number and 3. The larger number is also equal to 5 more than 3 times the sma

xenn [34]

Answer:

2 x minus y = negative 6 and 3 x minus y = negative 5

Step-by-step explanation:

y = 2(x+3) = 2x + 6 or 2x - y = -6

y = 5 + 3x or 3x - y = -5

7 0

3 years ago

Read 2 more answers

Select the basic integration formula you can use to find the indefinite integral.

kondaur [170]

Answer:

$\int \dfrac{du}{u}=\log|u|+C$

$\int u^n du=\dfrac{u^{n+1}}{n+1}+C$

$\int \dfrac{du}{u\sqrt{u^2-a^2}}=\dfrac{1}{a}\csc^{-1}(\dfrac{x}{a})+C$

Step-by-step explanation:

$\int \dfrac{du}{u}=\log|u|+C$ $[\because \int \dfrac{dx}{x}=\log |x|+C]$

$\int u^n du=\dfrac{u^{n+1}}{n+1}+C$ $[\because \int x^n dx=\dfrac{x^{n+1}}{n+1}+C]$

$\int \dfrac{du}{u\sqrt{u^2-a^2}}=\dfrac{1}{a}\csc^{-1}(\dfrac{x}{a})+C$ $[\because \dfrac{adx}{x\sqrt{x^2-a^2}}=\csc^{-1}(\dfrac{x}{a})+C]$

3 0

3 years ago