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zheka24 [161]
3 years ago
9

Six friends, four boys, and two girls went to a movie theater. They wanted to sit in a way so no girl sits on either first or la

st chair. How many such arrangements are possible?
Mathematics
2 answers:
goldfiish [28.3K]3 years ago
6 0

Answer: 5 valid arrangements

Step-by-step explanation:

This depends on whether the boys or girls swapping places are considered unique solutions.  I'm going to assume that is no, because there would be an unrealistic amount of solutions if it is true.

Assuming G = girl and B = boy, these are the possible arrangements.

(I will bold the valid solutions).

GGBBBB

GBGBBB

GBBGBB

GBBBGB

GBBBBG

BGGBBB

BGBGBB

BGBBGB

BGBBBG

BBGGBB

BBGBBG

BBBGGB

BBBBGG

Thus, there are 5 valid arrangements.

Hope it helps <3

GarryVolchara [31]3 years ago
6 0

Answer:

12 different arrangements because the roles of the girls could be switched around.

Step-by-step explanation:

b = boys

g= girls

1:

bggbbb

2:

bbggbb

3:

bbbggb

4:

bgbbgb

5:

bgbgbb

6:

bbgbgb

Hope this helped! Brainliest would be appreciated :)

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Step-by-step explanation:

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3 years ago
4. Decide whether the following rates are equivalent? Answer is either: YES or NO
Arte-miy333 [17]

Answer

Yes, they are equivalent.

Step-by-step explanation:

10x2=20

13x2=26

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3 years ago
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<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B3%7D%7B4%7D%20%20%2B%20%20%5Cfrac%7B1%7D%7B2%7D%20" id="TexFormula1" title=" \fra
Gnesinka [82]

Answer:

5/4

Step-by-step explanation:

You just need to multiply 1/2 by 2 to give you a common denominator:

3/4+2/4

From there you can add the numerators:

5/4

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2 years ago
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3 years ago
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In a geometric sequence, a4 = 54 and a7 = 1,458. what is the 12th term? <br><br> answer: B) 354,294
slamgirl [31]

Option B:

The 12th term is 354294.

Solution:

Given data:

a_4=54 and a_7=1458

To find a_{12}:

The given sequence is a geometric sequence.

The general term of the geometric sequence is a_n=a_1\ r^{n-1}.

If we have 2 terms of a geometric sequence a_n and a_k (n > K),

then we can write the general term as a_n=a_k\ r^{n-k}.

Here we have a_4=54 and a_7=1458.

So, n = 7 and k = 4 ( 7 > 4)

a_7=a_4\ .\ r^{7-4}

1458=54\ . \  r^3

This can be written as

$r^3=\frac{1458}{54}

$r^3=27

$r^3=3^3

Taking cube root on both sides of the equation, we get

r = 3

a_{12}=a_7\ .\ r^{12-7}

     =1458\ .\ r^5

     =1458\ .\ 3^5

a_{12}=354294

Hence the 12th term of the geometric sequence is 354294.

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2 years ago
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