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3 years ago

How do different function types compare?

1 answer:

6 0

They compare because there’s different problems to questions and different functions and some functions can match... your welcome:)

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If 22/15 = 23/x what is x equal to

KengaRu [80]

Answer:

15.68

Step-by-step explanation:

22/15=23/x

cross product

15*23=22*x

345=22x

x=345/22

x=15.68

7 0

3 years ago

The length of a rectangle is 4 feet more than the width. If the perimeter is 20 ft. What is the length of the rectangle?

Cloud [144]

Perimeter: P = 2L + 2W. In this problem L = W + 4 or W = L - 4. We want L, so let's eliminate W:

P = 2L + 2(L - 4) = 20 (all measurements in feet)

Simplifying,

2L + 2L - 8 = 20, or 4L = 28 ft. Thus, L = 7 ft.

The rectangle is 7 ft long.

3 0

3 years ago

Pamela has a 30-year, 5.75% mortgage on her $250,000 home. She has been

valentina_108 [34]

Answer:

$1424.10

Step-by-step explanation:

APEX is obnoxious, I understand.

4 0

3 years ago

Read 2 more answers

A school wishes to enclose its rectangular playground using 480 meters of fencing.

Harlamova29_29 [7]

Answer:

Part a) $A(x)=(-x^2+240x)\ m^2$

Part b) The side length x that give the maximum area is 120 meters

Part c) The maximum area is 14,400 square meters

Step-by-step explanation:

The picture of the question in the attached figure

Part a) Find a function that gives the area A(x) of the playground (in square meters) in terms of x

we know that

The perimeter of the rectangular playground is given by

$P=2(L+W)$

we have

$P=480\ m\\L=x\ m$

substitute

$480=2(x+W)$

solve for W

$240=x+W\\W=(240-x)\ m$

Find the area of the rectangular playground

The area is given by

$A=LW$

we have

$L=x\ m\\W=(240-x)\ m$

substitute

$A=x(240-x)\\A=-x^2+240x$

Convert to function notation

$A(x)=(-x^2+240x)\ m^2$

Part b) What side length x gives the maximum area that the playground can have?

we have

$A(x)=-x^2+240x$

This function represent a vertical parabola open downward (the leading coefficient is negative)

The vertex represent a maximum

The x-coordinate of the vertex represent the length that give the maximum area that the playground can have

Convert the quadratic equation into vertex form

$A(x)=-x^2+240x$

Factor -1

$A(x)=-(x^2-240x)$

Complete the square

$A(x)=-(x^2-240x+120^2)+120^2$

$A(x)=-(x^2-240x+14,400)+14,400$

$A(x)=-(x-120)^2+14,400$

The vertex is the point (120,14,400)

therefore

The side length x that give the maximum area is 120 meters

Part c) What is the maximum area that the playground can have?

we know that

The y-coordinate of the vertex represent the maximum area

The vertex is the point (120,14,400) -----> see part b)

therefore

The maximum area is 14,400 square meters

Verify

$x=120\ m$

$W=(240-120)=120\ m$

The playground is a square

$A=120^2=14,400\ m^2$

8 0

3 years ago

Answers to this question 8 2.5 12 3

ladessa [460]

Answer:

3 = ?

Step-by-step explanation:

The triangles are similar, so we can use ratios

15 12 -2

------ = --------------

15+? 12

15 10

------ = --------------

15+? 12

Using cross products

15 * 12 = 10 ( 15+?)

180 = 10 ( 15+?)

Divide each side by 10

18 = 15+?

Subtract 15 from each side

18-15 = 15+?-15

3 = ?

5 0

3 years ago